我有两个文件demo.PHP和post.PHP.我如何单身
页而不是两页.
demo.PHP
<html>
<head>
<title>Dynamic Form</title>
<script src="http://code.jquery.com/jquery-1.10.1.min.js" ></script>
<script>
$(document).ready(function(){
$("form").on('submit',function(event){
event.preventDefault();
data = $(this).serialize();
$.ajax({
type: "POST",
url: "post.PHP",
data: data
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
});
});
</script>
</head>
<body>
<form>
<table>
<tr>
<td>
<select name="one" onchange="if (this.value=='other'){this.form['other'].style.visibility='visible';this.form['submit'].style.visibility='visible'}else {this.form['other'].style.visibility='hidden';this.form['submit'].style.visibility='hidden'};">
<option value="" selected="selected">Select...</option>
<option value="India">India</option>
<option value="Pakistan">Pakistan</option>
<option value="Us">Us</option>
<option value="other">Other</option>
</select>
<input type="textBox" name="other" id="other" style="visibility:hidden;"/>
<input type="submit" name="submit" value="Add Country" style="visibility:hidden;"/>
</td>
</tr>
</table>
</form>
</body>
post.PHP
<?PHP
if(isset($_POST['other'])) {
$Country = $_POST['other'];
echo $Country;
}
?>
如何在demo.PHP中使用post.PHP数据而不将数据从一页传递到另一页.
解决方法:
更改您的ajax的URL
$.ajax({
type: "POST",
url: "demo.PHP",
data: data
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
<?PHP
if(isset($_POST['other'])) {
$Country = $_POST['other'];
echo $Country;
}
?>
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