android – 在viewpager中使用backstack和back按钮

我正在使用viewpager在片段之间滑动,并希望后退按钮导航到先前查看的片段而不是结束活动.很抱歉,如果这是 this question的副本,但我没有找到答案非常有帮助.显然onBackpressed需要被覆盖,但我不知道如何获取并显示正确的片段.我假设我应该使用fragmentmanager的backstack,但是getSupportFragmentManager().getBackStackEntryCount()总是返回0.我是否需要使用FragmentTransaction.addToBackStack()手动将片段添加到backstack？如果是这样,我会在适配器中添加它？

这是我活动的代码,

public class PagerActivity extends FragmentActivity {

ArrayList<Sale> sales;
MyAdapter mAdapter;
ViewPager mPager;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    Intent it = getIntent();
    this.sales = (ArrayList<Sale>) it.getExtras().get("sales");
    int position = it.getExtras().getInt("position");

    ActionBar actionBar = getActionBar();
    actionBar.setdisplayHomeAsUpEnabled(true);

    setContentView(R.layout.fragment_pager);
    mAdapter = new MyAdapter(getSupportFragmentManager());
    mPager = (ViewPager) findViewById(R.id.pager);
    mPager.setAdapter(mAdapter);
    mPager.setCurrentItem(position);

}

public class MyAdapter extends FragmentPagerAdapter {
    public MyAdapter(FragmentManager fragmentManager) {
        super(fragmentManager);
    }

    @Override
    public int getCount() {
        return sales.size();
    }

    @Override
    public void destroyItem(ViewGroup container,int position,Object object) {
        super.destroyItem(container,position,object);
    }

    @Override
    public Fragment getItem(int position) {
        SalesThumbFragment frag = new SalesThumbFragment();
        return frag.newInstance(sales.get(position));
    }
}

@Override
public boolean onoptionsItemSelected(MenuItem item) {
    switch (item.getItemId()) {
    case android.R.id.home:
        finish();
        return true;
    }
    return super.onoptionsItemSelected(item);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.sales_controller,menu);
    return true;
}

@Override
public void onBackpressed() {
  if(getSupportFragmentManager().getBackStackEntryCount() != 0) {
    getSupportFragmentManager().popBackStack();
  } else {

    super.onBackpressed();
  }
}


}

解决方法

在新设计支持库中,我使用它
我有同样的问题,我按照这一步

在viewpager中有3个片段的主要活动中,我创建堆栈
和推送和弹出数据.

//private Stack<Integer> stackkk;  ==> As i get edit suggestion 
private Stack<Integer> stackkk = new Stack<>(); // Edited 
private ViewPager mPager;
private int tabPosition = 0;



    mTabLayout.setupWithViewPager(mPager);
    mPager.addOnPagechangelistener(new TabLayout.TabLayoutOnPagechangelistener(mTabLayout));
    mTabLayout.setonTabSelectedListener(new TabLayout.OnTabSelectedListener() {
        @Override
        public void onTabSelected(TabLayout.Tab tab) {
            tabPosition = tab.getPosition();
            mPager.setCurrentItem(tab.getPosition());

            if (stackkk.empty())
                stackkk.push(0);

            if (stackkk.contains(tabPosition)) {
                stackkk.remove(stackkk.indexOf(tabPosition));
                stackkk.push(tabPosition);
            } else {
                stackkk.push(tabPosition);
            }
        }

        @Override
        public void onTabUnselected(TabLayout.Tab tab) {
            tabPositionUnselected = tab.getPosition();
        }

        @Override
        public void onTabReselected(TabLayout.Tab tab) {
        }
    });
}

并且在onBackpressed活动中,

@Override
public void onBackpressed() {
    if (stackkk.size() > 1) {
        stackkk.pop();
        mPager.setCurrentItem(stackkk.lastElement());
    } else {
    }
}