android – 无法解析为整数

好吧……我有这个.txt文件(UTF-8)

4661,SOMETHING,3858884120607,24,24.09
4659,SOMETHING1,3858884120621,15.95
4660,SOMETHING2,3858884120614,19.58

而这段代码

FileInputStream fis = new FileInputStream(new File(someTextFile.txt));
InputStreamReader isr = new InputStreamReader(fis,"UTF-8");
BufferedReader in = new BufferedReader(isr);

int i = 0;
String line;
while((line = in.readLine()) != null) {
Pattern p = Pattern.compile(",");
String[] article = p.split(line);

// I don't kNow why but when a first line starts with
// an integer - article[0] (which in .txt file is 4661)
// becomes someWeirdCharacter4661 so I need to trim it
// *weird character is like |=>|

if (i == 0) {
    StringBuffer articleCode = new StringBuffer(article[0]);
    articleCode.deleteCharat(0);
    article[0] = articleCode.toString();
}

SomeArticle**.addOrChange(mContext,Integer.parseInt(article[0]),article[1],article[2],Integer.parseInt(article[3]),Double.parseDouble(article[4]));

i++;
}

在模拟器上它很好但在真实设备(HTC Desire)上我得到这个(奇怪的)错误：

E/AndroidRuntime(16422): java.lang.NumberFormatException: unable to parse '4661' as integer

有什么问题？

**它只是我的类需要那些参数作为输入(context,int,string,double)

解决方法

它可能是你的文件不是UTF8或沿着那些行.

但是,如果你想破解修复,因为你只是一个解决方案对问题不感兴趣:)然后删除任何不是数字或小数点的东西.

String[] article = p.split(line);
Integer i = Integer.parseInt(article[0].replaceAll("[^0-9.]",""));

正则表达式并不完美(例如,它会影响…… 999 ….)但它会为你做.

编辑：

我似乎没有正确地阅读这个问题.如果只是在文件的开头那么你很可能是一个字节顺序标记,它用于告诉你文件是unicode还是UTF16 / 32,无论是小端还是大端端.你不需要经常看到它被使用.

http://unicode.org/faq/utf_bom.html#bom10