android – EditText不返回getText()上的内容

下面的代码片段显示了一个带有简单登录表单的Dialog.问题是当用户点击登录按钮时,输入到EditTexts的文本不会在getText() – 调用上返回.但是,如果我在xml-layout的EditTexts上设置 android：setText =“foo”,则在getText()上返回“foo”.知道为什么在运行时输入的文本不会粘住？

private void showLogindisplay() {
    loginDialog = new Dialog(GOfdroid.this);
    loginDialog.getwindow().setFlags(WindowManager.LayoutParams.FLAG_BLUR_BEHIND,WindowManager.LayoutParams.FLAG_BLUR_BEHIND);
    loginDialog.setTitle("Logga in");

    LayoutInflater li = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View dialogView = li.inflate(R.layout.login_dialog,null);
    loginDialog.setContentView(dialogView);

    loginDialog.show();

    Button loginButton = (Button) dialogView.findViewById(R.id.login_button);
    Button cancelButton = (Button) dialogView.findViewById(R.id.cancel_button);

    EditText unameView = (EditText) dialogView.findViewById(R.id.uname_id);
    if (unameView != null)
        Log.d(TAG,"unameView != null");
        Log.d(TAG,"uname.getText(): " + unameView.getText().toString());
        uname = unameView.getText().toString();

    EditText pwdView = (EditText) dialogView.findViewById(R.id.pwd_id);
    if (pwdView != null)    
        pwd = pwdView.getText().toString();

    Log.d(TAG,"uname = " + uname + ",pwd = " + pwd);

    loginButton.setonClickListener(new OnClickListener() {
        //@Override
        public void onClick(View v) {
            Log.d(TAG,"Clicked <logga in>");

            loginDialog.dismiss();

            viewEvents = new Runnable() {
                //@Override
                public void run() {
                    getEvents(uname,pwd);
                }
            };

            Thread thread =  new Thread(null,viewEvents,"MagentoBackground");
            thread.start();
            pDialog = ProgressDialog.show(GOfdroid.this,"Uppdaterar...","Hämtar registrerade körningar...",true);
        }
    });
}

和XML：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:paddingLeft="10dip"
    android:paddingRight="10dip"
>
<TextView
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="@string/uname_label"/>
<EditText
    android:id="@+id/uname_id"
    android:layout_width="220dip"
    android:layout_height="wrap_content"
    android:text="foo" />
<TextView
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="@string/pwd_label"
    android:paddingTop="10dip"/>
<EditText
    android:id="@+id/pwd_id"
    android:layout_width="220dip"
    android:layout_height="wrap_content"
    android:text=""
    android:inputType="textPassword" />
<LinearLayout
    android:orientation="horizontal"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:paddingTop="15dip"
>
<Button 
    android:id="@+id/login_button"
    android:layout_width="100dip"
    android:layout_height="fill_parent"
    android:text="Logga in" />
<Button 
    android:id="@+id/cancel_button"
    android:layout_width="100dip"
    android:layout_height="fill_parent"
    android:text="Avbryt" />
</LinearLayout>
</LinearLayout>

解决方法

问题是你没有在匿名内部类中更新uname和pwd.只有在调用showLogindisplay()方法时才更新uname和pwd.当用户更改文本并点击登录按钮时,将调用onClick()方法.

在你想要做的内部类的onClick()方法中：

uname = unameView.getText();
pwd = pwdView.getText();

您必须创建unameView和pwdView全局/字段变量,因此匿名内部类可以访问它们.

你必须这样做的原因是因为当按下登录按钮时,只运行具有匿名内部类的onClick的代码.

我希望能解决这个问题.