linux – 如何使shell脚本自动化并读取当前时间？

我有一个非常重要的问题,我一直是cowsay(包装)的剑龙的粉丝,它读取财富,输入等等.所以很自然地,让这个雄伟的生物告诉我它的哪一天是非常重要的.每天.我使用用户输入做了以下脚本：

#!/bin/bash

selection=
until [ "$selection" = "0" ]; do
        echo ""
        echo "PROGRAM MENU"
        echo "1 - It's Monday!"
        echo "2 - It's Tuesday!"
        echo "3 - It's Wednesday!"
        echo "4 - It's Thursday!"
        echo "5 - It's Friday!"
        echo "6 - Custom input"
        echo "7 - Exit"
        echo ""
        echo -n "Enter selection: "
        read selection
        echo ""
        case $selection in
                1 ) cowsay -f stegosaurus "It's Monday!"
                 exit ;;
                2 ) cowsay -f stegosaurus "It's Tuesday!"
                 exit ;;
                3 ) cowsay -f stegosaurus "It's Wednesday!"
                 exit ;;
                4 ) cowsay -f stegosaurus "It's Thursday!"
                 exit ;;
                5 ) cowsay -f stegosaurus "It's Friday!"
                 exit ;;
                6 ) echo -n "custom input > "
                 read custom
                 cowsay -f stegosaurus "$custom"
                 exit ;;
                7 ) exit ;;
                * ) cowsay -f stegosaurus "Guess what day it is?"
                 exit ;;
        esac
done

然而,这是我在Linux发行版上的第一个脚本之一,我已准备好通过使其在当天自动更新来增强我的创作(如果可以的话,甚至可能是小时).但是,到目前为止我还没能做到这一点.任何人都可以帮助我或指出我正确的方向吗？

我非常感谢任何建议,非常感谢！

解决方法:

cowsay -f stegosaurus "It's $(date +%A)"

查看GNU date documentation以获取有关如何格式化时间的更多示例.例如

cowsay -f stegosaurus "It's $(date +%A) and the time is $(date +%r)"