数组 – 如果数组来自源文件,则通过bash中的索引访问数组不起作用

当我通过索引访问数组时,如果数组是在另一个bash脚本的源代码中导入的变量,我会得到奇怪的行为.是什么原因导致这种行为？它如何被修复,所以来自另一个bash脚本的数组的行为与从运行脚本中定义的数组相同？

${numbers [0]} evals to“one two three”而不是“one”,因为它应该是.我试图演示这个行为的全面测试如下所示：

test.sh的来源：

#!/bin/bash

function test {

    echo "Length of array:"
    echo ${#numbers[@]}

    echo "Directly accessing array by index:"
    echo ${numbers[0]}
    echo ${numbers[1]}
    echo ${numbers[2]}

    echo "Accessing array by for in loop:"
    for number in ${numbers[@]}
    do
        echo $number
    done

    echo "Accessing array by for loop with counter:"
    for (( i = 0 ; i < ${#numbers[@]} ; i=$i+1 ));
    do
        echo $i
        echo ${numbers[${i}]}
    done
}

numbers=(one two three)
echo "Start test with array from within file:"
test 

source numbers.sh
numbers=${sourced_numbers[@]}
echo -e "\nStart test with array from source file:"
test

来源of.sh：

#!/bin/bash
#Numbers

sourced_numbers=(one two three)

test.sh的输出：

Start test with array from within file:
Length of array:
3
Directly accessing array by index:
one
two
three
Accessing array by for in loop:
one
two
three
Accessing array by for loop with counter:
0
one
1
two
2
three

Start test with array from source file:
Length of array:
3
Directly accessing array by index:
one two three
two
three
Accessing array by for in loop:
one
two
three
two
three
Accessing array by for loop with counter:
0
one two three
1
two
2
three

这个问题与采购无关.这是因为作业编号= ${sourced_numbers [@]}不会执行您的想法.它将数组(sourced_numbers)转换成一个简单的字符串,并将其存储在数字的第一个元素中(在接下来的两个元素中留下“两个”“三”).要将其复制为数组,请改用数字=(“${sourced_numbers [@]}”).

对于${numbers [@]}中的数字来说,BTW是循环遍历数组元素的错误方式,因为它将会在元素中的空格上破坏(在这种情况下,数组包含“一二三”“二”三“,但循环运行为”一“,”二“,”三“,”三“).用于“${numbers [@]}”中的号码.实际上,很容易得到双引号的习惯,几乎所有的变量替换(例如echo“${numbers {${i}]}”),因为这不是让他们不引用的唯一的地方可能会导致麻烦.