意外令牌附近的语法错误“(”在bash中声明数组时

我必须对我的一些EAR进行几次maven测试.

我不想手动执行它们,而是编写一个自动执行该过程的shell脚本.

这就是我所拥有的：

#!/bin/bash
projects = ("MAIN_EAR","EJB_EAR","SIT_EAR","ENC_EAR","ENVIRONMENT_EAR","PRESS_EAR")

myenvs  = ("dev","cart")

for prj in "${projects[@]}"
do
    :
    for myenv in "${myenvs[@]}"
    do
       :
       mvn –am –pl "../$prj" clean package –Denvironment=$myenv
    done
done

这是输出：

back@slash-PC:~/workspace/WSP$bash maven_tests.sh
maven_tests.sh: line 2: Syntax error near unexpected token "("
maven_tests.sh: line 2: `projects = ("MAIN_EAR","PRESS_EAR")

似乎bash不喜欢我如何声明数组.

我错过了什么？

如果它有帮助：我在Xubuntu 14.04 x64上

解决方法

声明BASH数组时会出现一些语法错误. (数组声明中的空格=在数组元素之间使用逗号).

试试这段代码：

#!/bin/bash
projects=("MAIN_EAR" "EJB_EAR" "SIT_EAR" "ENC_EAR" "ENVIRONMENT_EAR" "PRESS_EAR")

myenvs=("dev" "cart")

for prj in "${projects[@]}"; do
    for myenv in "${myenvs[@]}"; do
       mvn –am –pl "../$prj" clean package –Denvironment="$myenv"
    done
done