HDOJ 题目4099 Revenge of Fibonacci大数, 字典树

Revenge of Fibonacci

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 204800/204800 K (Java/Others)
Total Submission(s): 2405    Accepted Submission(s): 609

Problem Description

The well-kNown Fibonacci sequence is defined as following:


  Here we regard n as the index of the Fibonacci number F(n).
  This sequence has been studied since the publication of Fibonacci's book Liber Abaci. So far,many properties of this sequence have been introduced.
  You had been interested in this sequence,while after reading lots of papers about it. You think there’s no need to research in it anymore because of the lack of its unrevealed properties. Yesterday,you decided to study some other sequences like Lucas sequence instead.
  Fibonacci came into your dream last night. “Stupid human beings. Lots of important properties of Fibonacci sequence have not been studied by anyone,for example,from the Fibonacci number 347746739…”
  You woke up and Couldn’t remember the whole number except the first few digits Fibonacci told you. You decided to write a program to find this number out in order to continue your research on Fibonacci sequence.

 

Input

  There are multiple test cases. The first line of input contains a single integer T denoting the number of test cases (T<=50000).
  For each test case,there is a single line containing one non-empty string made up of at most 40 digits. And there won’t be any unnecessary leading zeroes.

 

Output

  For each test case,output the smallest index of the smallest Fibonacci number whose decimal notation begins with the given digits. If no Fibonacci number with index smaller than 100000 satisfy that condition,output -1 instead – you think what Fibonacci wants to told you beyonds your ability.

 

Sample Input

  
  

   
   15
1
12
123
1234
12345
9
98
987
9876
98765
89
32
51075176167176176176
347746739
5610
  
  

 

Sample Output

  
  

   
   Case #1: 0
Case #2: 25
Case #3: 226
Case #4: 1628
Case #5: 49516
Case #6: 15
Case #7: 15
Case #8: 15
Case #9: 43764
Case #10: 49750
Case #11: 10
Case #12: 51
Case #13: -1
Case #14: 1233
Case #15: 22374
  
  

 

Source

2011 Asia Shanghai Regional Contest

 

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lcy   |   We have carefully selected several similar problems for you:   4091  4097  4096  4093  4092 

 

坑题啊、、

ac代码

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
char a[100],b[100],c[100],t[100];
typedef struct s
{
	struct s * child[10];
	int id;
}node,*Node;
Node root;
void add(char a[],char b[],char c[])  
{  
    int len1,len2,i,j,t[10000],max,k=0;  
    len1=strlen(a);  
    len2=strlen(b);  
    i=len1-1;  
    j=len2-1;  
    memset(t,sizeof(t));  
    while(i>=0||j>=0)  
    {  
        if(i<0&&j>=0)  
            t[k]+=b[j]-'0';  
        else  
            if(j<0&&i>=0)  
                t[k]+=a[i]-'0';  
            else  
            {  
                t[k]+=a[i]-'0'+b[j]-'0';  
            }  
        k++;  
        t[k]+=t[k-1]/10;  
        t[k-1]%=10;  
        if(t[k])  
            max=k;  
        else  
            max=k-1;  
        i--;  
        j--;  
    }  
    for(i=max;i>=0;i--)  
        c[max-i]=t[i]+'0';  
    c[max+1]='\0';  
    //return c;  
}  
char str[3][100];
void insert(char *s,int id)
{
	Node cur,newnode;
	int i,Now,len;
	len=strlen(s);
	cur=root;
	//int i;
	for(i=0;i<len&&i<41;i++)
	{
		Now=s[i]-'0';
		if(cur->child[Now]!=NULL)
		{
			cur=cur->child[Now];
		}
		else
		{
			newnode=(Node)calloc(1,sizeof(node));
			cur->child[Now]=newnode;
			cur=cur->child[Now];
			cur->id=id;
		}
	}
}
int seach(char *s)
{
	int len=strlen(s),i;
	Node cur;
	cur=root;
	for(i=0;i<len;i++)
	{
		int Now=s[i]-'0';
		if(cur->child[Now]==NULL)
			break;
		cur=cur->child[Now];
	}
	if(i<len)
		return -1;
	return cur->id;
}
void fun()
{
	strcpy(a,"1");
	insert(a,0);
	strcpy(b,"1");
	insert(b,1);
	for(int i=2;i<100000;i++)
	{
		int len1=strlen(a);
		int len2=strlen(b);
		if(len2>60)
		{
			b[len2-1]=0;
			a[len1-1]=0;
		}
		add(a,b,t);
		insert(t,i);
		strcpy(a,b);
		strcpy(b,t);
	//	if(i<30)
	//		printf("%s\n",t);
	}
}
int main()
{
	int t,c=0;
	root=(Node)calloc(1,sizeof(node));
	fun();
	scanf("%d",&t);
	while(t--)
	{
		char temp[50];
		scanf("%s",temp);
		printf("Case #%d: ",++c);
		printf("%d\n",seach(temp));
	}
}