HDU 1212 Big Number水题大数取模

Big Number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 4556    Accepted Submission(s): 3152

Problem Description

As we kNow,Big Number is always troublesome. But it's really important in our ACM. And today,your task is to write a program to calculate A mod B.

To make the problem easier,I promise that B will be smaller than 100000.

Is it too hard? No,I work it out in 10 minutes,and my program contains less than 25 lines.

 

Input

The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000,and B will be smaller than 100000. Process to the end of file.

 

Output

For each test case,you have to ouput the result of A mod B.

 

Sample Input

  
  

   
   2 3
12 7
152455856554521 3250
  
  

 

Sample Output

  
  

   
   2
5
1521
  
  

AC代码：

#include<stdio.h>
#include<string.h>
int main(){
	char a[1010];
	int i,len,ans,b;
	while(~scanf("%s%d",a,&b)){
		len=strlen(a);
		ans=0;
		for(i=0;i<len;i++)
			ans=(ans*10+(a[i]-'0'))%b;
		printf("%d\n",ans);
	}
	return 0;
}