c – 删除的构造函数/运算符的可访问性是否重要？

如果一个类型的默认成员被删除,那么这个声明的可访问性是什么呢？

class FooA {
public:
  FooA() = delete;
  FooA(FooA const&) = delete;
  FooA& operator=(FooA const&) = delete;
}

class FooB {
private:
  FooB() = delete;
  FooB(FooB const&) = delete;
  FooB& operator=(FooB const&) = delete;
}

class FooC {
protected:
  FooC() = delete;
  FooC(FooC const&) = delete;
  FooC& operator=(FooC const&) = delete;
}

解决方法

虽然 accessibility and deletedness are orthogonal,很难看出在你提出的情况下如何有实际的区别.

原文地址：https://www.jb51.cc/c/113605.html