iPhone – 获取两个日期之间的天数

我正在为iPhone编写一个GTD应用程序.对于应有的任务,我希望显示诸如“明天到期”或“到期日”或“到期7月18日”之类的内容.显然,即使任务距离不到24小时,我也需要显示“明天”(例如,用户在星期六晚上11点检查,并在周日早上8点看到任务).所以,我写了一个方法来获取两个日期之间的天数.这是代码……

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd-HH-mm"];

NSDate *NowDate = [dateFormatter dateFromString:@"2010-01-01-15-00"];
NSDate *dueDate = [dateFormatter dateFromString:@"2010-01-02-14-00"];

NSLog(@"NSDate *NowDate = %@",NowDate);
NSLog(@"NSDate *dueDate = %@",dueDate);

NSCalendar *calendar = [NSCalendar currentCalendar];

NSDateComponents *differenceComponents = [calendar components:(NSDayCalendarUnit)
                                                     fromDate:NowDate
                                                       toDate:dueDate
                                                      options:0];

NSLog(@"Days between dates: %d",[differenceComponents day]);

……这是输出：

NSDate *NowDate = 2010-01-01 15:00:00 -0700
NSDate *dueDate = 2010-01-02 14:00:00 -0700
Days between dates: 0

如您所见,该方法返回不正确的结果.它应该返回1作为两天之间的天数.我在这做错了什么？

编辑：我写了另一种方法.我没有进行过广泛的单元测试,但到目前为止似乎有效：

+ (NSInteger)daysFromDate:(NSDate *)fromDate inTimeZone:(NSTimeZone *)fromTimeZone untilDate:(NSDate *)toDate inTimeZone:(NSTimeZone *)toTimeZone {

    NSCalendar *calendar = [NSCalendar currentCalendar];
    unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;

    [calendar setTimeZone:fromTimeZone];
    NSDateComponents *fromDateComponents = [calendar components:unitFlags fromDate:fromDate];

    [calendar setTimeZone:toTimeZone];
    NSDateComponents *toDateComponents = [calendar components:unitFlags fromDate:toDate];

    [calendar setTimeZone:[NSTimeZone defaultTimeZone]];
    NSDate *adjustedFromDate = [calendar dateFromComponents:fromDateComponents];
    NSDate *adjustedToDate = [calendar dateFromComponents:toDateComponents];

    NSTimeInterval timeIntervalBetweenDates = [adjustedToDate timeIntervalSinceDate:adjustedFromDate];
    NSInteger daysBetweenDates = (NSInteger)(timeIntervalBetweenDates / (60.0 * 60.0 * 24.0));

    NSDateComponents *midnightBeforeFromDateComponents = [[NSDateComponents alloc] init];
    [midnightBeforeFromDateComponents setYear:[fromDateComponents year]];
    [midnightBeforeFromDateComponents setMonth:[fromDateComponents month]];
    [midnightBeforeFromDateComponents setDay:[fromDateComponents day]];

    NSDate *midnightBeforeFromDate = [calendar dateFromComponents:midnightBeforeFromDateComponents];
    [midnightBeforeFromDateComponents release];

    NSDate *midnightAfterFromDate = [[NSDate alloc] initWithTimeInterval:(60.0 * 60.0 * 24.0)
                                                               sinceDate:midnightBeforeFromDate];

    NSTimeInterval timeIntervalBetweenToDateAndMidnightBeforeFromDate = [adjustedToDate timeIntervalSinceDate:midnightBeforeFromDate];
    NSTimeInterval timeIntervalBetweenToDateAndMidnightAfterFromDate = [adjustedToDate timeIntervalSinceDate:midnightAfterFromDate];

    if (timeIntervalBetweenToDateAndMidnightBeforeFromDate < 0.0) {

        // toDate is before the midnight before fromDate

        timeIntervalBetweenToDateAndMidnightBeforeFromDate -= daysBetweenDates * 60.0 * 60.0 * 24.0;

        if (timeIntervalBetweenToDateAndMidnightBeforeFromDate < 0.0)
            daysBetweenDates -= 1;
    }
    else if (timeIntervalBetweenToDateAndMidnightAfterFromDate >= 0.0) {

        // toDate is after the midnight after fromDate

        timeIntervalBetweenToDateAndMidnightAfterFromDate -= daysBetweenDates * 60.0 * 60.0 * 24.0;

        if (timeIntervalBetweenToDateAndMidnightAfterFromDate >= 0.0)
            daysBetweenDates += 1;
    }

    [midnightAfterFromDate release];

    return daysBetweenDates;
}

解决方法

从组件的文档：fromDate：toDate：options ::

The result is lossy if there is not a small enough unit requested to hold the full precision of the difference.

由于差异小于一整天,因此它正确返回0天的结果.