c#以递归方式迭代嵌套属性列表

foreach (Targetobject innerObject1 in complexObject.InnerObjects) { 
    foreach (Targetobject innerObject2 in innerObject1.InnerObjects) { 
        foreach (Targetobject innerObject3 in innerObject2.InnerObjects) { 
           yield return innerObject3;
        } 
        yield return innerObject2;
    } 
    yield return innerObject1;
 }

我怎么能这么做呢？我需要将这些嵌套列表中捕获的Targetobject的所有实例聚合到一个列表中.这是一次无效的尝试.

public static IEnumerable<Targetobject> GetRecursively(params Targetobject[] startingObjects) 
    {
        foreach (Targetobject startingObject in startingObjects) 
        {
            foreach (Targetobject innerObject in GetRecursively(startingObject.InnerObjects.ToArray()))
            {
                yield return innerObject;
            }
            yield return startingObject;
        }
    }

解决方法

像这样 – 产生startingObject,并为InnerObjects中的每个项递归调用：

public static IEnumerable<Targetobject> GetRecursively(Targetobject startingObject) 
{
    yield return startingObject;
    if (startingObject.InnerObjects != null)
        foreach (Targetobject innerObject in startingObject.InnerObjects.ToArray())
            foreach (Targetobject recursiveInner in GetRecursively(innerObject))
                yield return recursiveInner;
}

要支持数组作为参数,请围绕它包装foreach：

public static IEnumerable<Targetobject> GetRecursively2(params Targetobject[] startingObjects)
{
    foreach (Targetobject startingObject in startingObjects)
    {
        yield return startingObject;
        if (startingObject.InnerObjects != null)
            foreach (Targetobject innerObject in startingObject.InnerObjects.ToArray())
                foreach (Targetobject recursiveInner in GetRecursively(innerObject))
                    yield return recursiveInner;
    }
}