添加CASE语句的结果

如何解决添加CASE语句的结果

您END在CASE声明中缺少：

SELECT
  surname,
  givenname,
  (CASE WHEN surname = 'Smith' THEN 2 ELSE 0 END)  -- < add END
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0 END)  -- < add END
    AS score
FROM person
WHERE (surname = 'Smith' AND givenname LIKE 'J%')
  OR  (surname LIKE 'S%' AND givenname = 'John')
  OR  (surname = 'John' AND givenname LIKE 'S%')
  OR  (surname LIKE 'J%' AND givenname = 'Smith')
ORDER BY
  score DESC,
  surname ASC,
  givenname ASC;

解决方法

我有以下Oracle
SQL查询。在给定名称和姓氏的情况下，它会以任一顺序查找所有带有一个名字和另一个名字首字母的记录。我创建了该score列，以将可能的匹配项放置在结果集的顶部。

SELECT
  surname,givenname,(CASE WHEN surname = 'Smith' THEN 2 ELSE 0)
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0)
    AS score
FROM person
WHERE (surname = 'Smith' AND givenname LIKE 'J%')
  OR  (surname LIKE 'S%' AND givenname = 'John')
  OR  (surname = 'John' AND givenname LIKE 'S%')
  OR  (surname LIKE 'J%' AND givenname = 'Smith')
ORDER BY
  score DESC,surname ASC,givenname ASC;

问题是score在的位置给出了错误+。IDE报告：

语法错误，应为：
/
*
|

以及执行报告：

SQL错误：ORA-00905：缺少关键字

我究竟做错了什么？有没有更好的方法来计算分数？