如何解决使用深度优先搜索转换二维数组中的树
[[10,5,3,3]]
[[10,-2]]
[[10,2,1]]
[[10,-3,11]]
解决方法
public int ConvertToArray(TreeNode root,int targetSum) {
ArrayList<ArrayList<Integer>> paths = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> path = new ArrayList<Integer>();
ConvertToArray(root,paths,path);
return 1;
}
public void ConvertToArray(TreeNode root,ArrayList<ArrayList<Integer>> paths,ArrayList<Integer> path)
{
if(root == null)
{
var currpath = new ArrayList<>(path);
paths.add(currpath);
return;
}
path.add(root.val);
ConvertToArray(root.left,path);
ConvertToArray(root.right,path);
path.remove(path.size()-1);
}
}
,
您可以检查此实现。
import java.util.Scanner;
import java.util.Stack;
import java.util.stream.Collectors;
public class Main {
static class Node {
int value;
Node right;
Node left;
Node(int value) {
this.value = value;
}
@Override
public String toString() {
return "" + value;
}
public boolean isLeaf() {
return right == null && left == null;
}
}
public static void main(String[] args) {
String input = "10 5 -3 3 2 3 -2 N N N N N 1 N N N 11 N N";
Scanner scanner = new Scanner(input);
Node root = new Node(scanner.nextInt());
parse(scanner,root);
print(root);
}
private static void parse(Scanner scanner,Node node) {
if (!scanner.hasNext("N")) {
node.left = new Node(scanner.nextInt());
} else {
scanner.next();
}
if (!scanner.hasNext("N")) {
node.right = new Node(scanner.nextInt());
} else {
scanner.next();
}
if (node.left != null) {
parse(scanner,node.left);
}
if (node.right != null) {
parse(scanner,node.right);
}
}
private static void print(Node node) {
Stack<Node> stack = new Stack<>();
stack.push(node);
print(node,stack);
}
private static void print(Node node,Stack<Node> stack) {
if (node.isLeaf()) {
print(stack);
} else {
if (node.left != null) {
stack.push(node.left);
print(node.left,stack);
}
if (node.right != null) {
stack.push(node.right);
print(node.right,stack);
}
}
stack.pop();
}
private static void print(Stack<Node> stack) {
String values = stack.stream().map(s -> "" + s.value).collect(Collectors.joining(","));
System.out.println("[[" + values + "]]");
}
}
输出
[[10,5,3,3]]
[[10,-2]]
[[10,2,1]]
[[10,-3,11]]
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