如何解决Javascript通过互值减少对象数组
如何将对象数组减少到新的合并对象数组? 我将以下数组与地方及其子区域混合在一起。我想将 sub_main_places 添加到 main_places,如下所示:
"unformatted places": [
{
"name": "main_place1","address": "place_address1"
},{
"name": "main_place2","address": "place_address2"
},{
"name":"sub_main_place1","address":"sub_main_place_address1"
},{
"name":"sub_main_place2","address":"sub_main_place_address2"
}
]
我想要达到的结果是:
"formatted places": [
{
"name": "main_place1","address": "place_address1","sub_area": "sub_main_place1"
},"address": "place_address2","sub_area": "sub__main_place2"
}
],
解决方法
使用reduce,你可以用与主地址对应的键组合一个对象,然后在遇到子地址时引用这些键。最后,您可以将结果转换回带有 Object.values
的数组let unformatted_places = [{
"name": "main_place1","address": "place_address1"
},{
"name": "main_place2","address": "place_address2"
},{
"name": "sub_main_place1","address": "sub_main_place_address1"
},{
"name": "sub_main_place2","address": "sub_main_place_address2"
}
]
let formatted_places = Object.values(unformatted_places
.sort((a,b) => a.name.localeCompare(b.name))
.reduce((b,a) => {
let f = a.name.split('sub_')[1]
if (a.name.indexOf('sub_') === 0 && b[f]) {
b[f].sub_area = a.name;
} else {
b[a.name] = a;
}
return b;
},{}))
console.log(formatted_places);
尝试了另一种方式:
let data_1 = {
"unformatted places": [{
"name": "main_place1","address": "place_address1"
},{
"name": "main_place2","address": "place_address2"
},{
"name": "sub_main_place1","address": "sub_main_place_address1"
},{
"name": "sub_main_place2","address": "sub_main_place_address2"
}
]
};
let data_2 = {}
data_1["unformatted places"].forEach(function(dict) {
var name = dict.name;
if (name.startsWith("main")) {
data_2[name] = dict;
} else if (name.startsWith("sub_")) {
let key = name.substring(4,name.length);
if (key in data_2) {
data_2[key]["sub_area"] = name;
} else {
data_2[key] = {
"sub_area": name
};
}
}
});
data_2 = {
"formatted places": Object.values(data_2)
}
console.log(data_2);
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