在 Angular 中访问自定义装饰器内的服务

如何解决在 Angular 中访问自定义装饰器内的服务

我正在 angular/typescript 中创建一个自定义装饰器：@feature(featureName) 它将输入作为 featureName 的字符串并调用服务以检查该功能是否已启用。

我无法将服务注入到装饰器中，因此使用了各种方法。任何可能的解决方案？ feature.decorator.ts

// eslint-disable-next-line @typescript-eslint/ban-types
export function feature(flag: string) {
    return function (target: Object,key: string | symbol) {
        Object.defineProperty(target,key,{
            configurable: false,enumerable: false,get: () => {
                return 'newValue';
            },set: () => {
                return 'new value';
            }
        })
    }
}

我的服务是单例服务：

import { BehaviorSubject,Observable } from 'rxjs';

import { BaseAPIService } from '../../services/base-api.service';
import { FEATURE } from './features-list.constants';
import { Injectable } from '@angular/core';
import { map } from 'rxjs/operators';

export interface FeatureStatus {
  feature: string;
  status: boolean;
}
@Injectable({ providedIn: 'root' })
export class FeatureManagerService {
  private _featureStatuses: FeatureStatus[];
  areFlagsAvailable$: BehaviorSubject<boolean> = new BehaviorSubject(false);
  constructor(private httpService: BaseAPIService) {}

  loadFeatureFlags(): Observable<boolean> {
    return this.fetchFeatureStatus().pipe(
      map((featureStatuses: FeatureStatus[]) => {
        console.log("FMS first");
        this._featureStatuses = featureStatuses;
        features = featureStatuses;
        this.areFlagsAvailable$.next(true);
        return true;
      })
    );
  }

  fetchFeatureStatus(): Observable<FeatureStatus[]> {
    const features = [];
    for (const feature of Object.keys(FEATURE)) {
      features.push(feature);
    }
    return this.httpService.post(`/api/feature-flag`,features);
  }

  isFeatureEnabled(featureName: string): boolean {
    return this._featureStatuses.filter((featureStatus) => {
      return featureStatus.feature === featureName;
    })[0].status;
  }
}

解决方法

你的代码有点模糊。据我了解，将服务放入构造函数时会出错，所以这是我的解决方案

@Inject(BaseAPIService private httpService: any

希望这会有所帮助