sqlite 计入列

如何解决sqlite 计入列

我收到了 2 个查询，2 个计数。但是，当我编写语句 count()、count() 时，两列的计数都相同。你能帮我吗？

我已经尝试了不同的方法（最后一个例子）

这是我的两个单独的查询

SELECT 
    x.ROWa,x.ROWb,COUNT(*) ResultA 
FROM
    tableA x
LEFT JOIN 
    tableB AS y ON SUBSTR(x.ROWb,4,1) = y.ROWz
WHERE 
    x.ROWc IN (5,6) 
    AND (SUBSTR(x.ROWb,1) = "6" OR SUBSTR(x.ROWb,1) = "9") 
    AND Workflow = "VALUEone" 
    AND Shorthistory = "False"
GROUP BY 
    1
ORDER BY
    3 DESC,2,1 ASC

SELECT 
    x.ROWa,COUNT(*) ResultB 
FROM
    tableA x
LEFT JOIN 
    tableB AS y ON SUBSTR(x.ROWb,1) = "9") 
    AND Status = "successfull"
GROUP BY
    1
ORDER BY
    3 DESC,1 ASC

我得到的是：

ROWa|ROWb|ResultA|ResultB
-------------------------
aaa |123 |78    |78
bbb |456 |30    |30

但它应该给出实际结果：

ROWa|ROWb|ResultA|ResultB
-------------------------
aaa |123 |78    |250
bbb |456 |30    |74

我尝试了什么：

SELECT 
    x.ROWa,COUNT((SELECT x.ROWb 
           FROM tableA x
           LEFT JOIN tableB AS y ON SUBSTR(x.ROWb,1) = y.ROWz
           WHERE x.ROWc IN (5,6) 
             AND (SUBSTR(x.ROWb,1) = "9") 
             AND Workflow = "VALUEone" 
             AND Shorthistory = "False"
           GROUP BY 1)) ResultA,1) = "9") 
             AND Status = "successfull"
           GROUP BY 1)) ResultB
GROUP BY
    1
ORDER BY
    3 DESC,1 ASC

解决方法

如果使用条件聚合，您可以将 2 个查询合并为 1 个：

SELECT x.ROWa,x.ROWb,COUNT(CASE WHEN Workflow = 'VALUEone' AND Shorthistory = 'False' THEN 1 END) ResultA,COUNT(CASE WHEN Status = 'successfull' THEN 1 END) ResultB  
FROM tableA x LEFT JOIN tableB y 
ON SUBSTR(x.ROWb,4,1) = y.ROWz
WHERE x.ROWc in (5,6) AND SUBSTR(x.ROWb,1) IN ('6','9') 
GROUP BY x.ROWa

或者：

SELECT x.ROWa,SUM(Workflow = 'VALUEone' AND Shorthistory = 'False') ResultA,SUM(Status = 'successfull') ResultB  
FROM tableA x LEFT JOIN tableB y 
ON SUBSTR(x.ROWb,'9')  
GROUP BY x.ROWa