如何解决Python tkinter Treeview 列比指定的多
listBox = ttk.Treeview(
tab_player,columns=('Player','rating','Price'),selectmode="extended",)
listBox.heading('#0',text='Player',anchor=tk.CENTER)
listBox.heading('#1',text='rating',anchor=tk.CENTER)
listBox.heading('#2',text='Price',anchor=tk.CENTER)
listBox.column('#0',stretch=tk.YES,minwidth=50,width=80)
listBox.column('#1',width=20)
listBox.column('#2',width=30)
listBox.grid(row=5,column=5,rowspan=7,sticky=W)
我的插入函数如下：
def insertitem():
GUI.listBox.insert('','end',values = (GUI.listBox_content.get(),GUI.listBoxr_content.get(),GUI.listBox_content_price.get()))
当我启动我的应用程序时，我有一个额外的列，插入的数据不是我想要的（数据在错误的列中）。
这是为什么？
解决方法
列# include<iostream>
# include<conio.h>
# include<stdio.h>
# include<stdlib.h>
# include<windows.h>
# include<cstdlib>
# include<math.h>
using namespace std;
int main()
{
char Loai_math_problem;
int Cau_tra_loi;
int x,So_hang_thu_nhat,So_hang_con_lai,Tong;
int So_tru,So_bi_tru,Hieu;
int Thua_so_thu_nhat,Thua_so_thu_hai,Thua_so_con_lai,Tich;
int So_chia,So_bi_chia,Thuong;
system("cls");
printf("Short program made by C++ can solve X from a math problem with a sign (+,-,x,/).\nVer1.2.");
Sleep(1200);
printf("\nPress any key to continue!");
cau_tra_loi_chung://label chung
getch();
system("cls");
printf("Okey! Let' start!\nType '+','-','x','/' to confirm.");
Loai_math_problem=getch();
switch(Loai_math_problem)
{
case '+'://label +
{
buoc_tra_loi_phan_1:
printf("\nOkey!\nWhat type of 'x'?\nType '1' in case like 1+4=x or '2' in case x+1=5 also 1+x=5\n");
scanf("%i",Cau_tra_loi);
if(Cau_tra_loi==1)
{
printf("\nType the '1': ");
scanf("%i",So_hang_thu_nhat);
printf("\nType the '4': ");
scanf("%i",So_hang_con_lai);
printf(endl("X: %i",So_hang_thu_nhat + So_hang_con_lai)endl);//cout << endl << "X: " << So_hang_thu_nhat + So_hang_con_lai << endl;
}
if (Cau_tra_loi == 2)
{
printf("Type the '1': \n");
scanf("%i",So_hang_con_lai);
printf("Type the '5': \n");
scanf("%i",Tong);
printf("X: %i",Tong - So_hang_con_lai endl);//cout << "X: " << Tong - So_hang_con_lai << endl;
}
if(Cau_tra_loi<=0 ||Cau_tra_loi>=3)
{
printf("\nError: Invailid answer");
}
break;
}
case '-':
{
buoc_tra_loi_phan_2://label -
printf("\nOkey!\nWhat type of 'x'?\nType '1' in case like 4-1=x or '2' in case x-1=3 or '3' 4-x=3\n");
Cau_tra_loi=getch();
if (Cau_tra_loi == 1)
{
printf("\nType the '4': ");
scanf("%i",So_bi_tru);
printf("\nType the '1': ");
scanf("%i",So_tru);
printf(endl"X: %i",So_bi_tru - So_tru endl);//cout << endl << "X: " << So_bi_tru - So_tru << endl;
}
if (Cau_tra_loi == 2)
{
printf("Type the '1': \n");
scanf("%i",So_tru);
printf("Type the '3': \n");
scanf("%i",Hieu);
printf("X: %i",So_tru + Hieu endl);//cout << "X: " << So_tru + Hieu << endl;
}
if (Cau_tra_loi == 3)
{
printf("Type the '4': \n");
scanf("%i",So_bi_tru);
printf("Type the '3': \n");
scanf("%i",So_bi_tru - Hieu endl);//cout << "X: " << So_bi_tru - Hieu << endl;
}
if(Cau_tra_loi<=0 || Cau_tra_loi>=4)
{
printf("\nError: Invailid answer");
}
break;
}
case 'x':
{
buoc_tra_loi_phan_3://label x
printf("\nOkey!\nWhat type of 'x'?\nType '1' in case like 1 x 5 = X or '2' in case X x 1 = 5 also 1 x X = 5\n");
Cau_tra_loi=getch();
if (Cau_tra_loi == 1)
{
printf("\nType the '1': ");
scanf("%i",Thua_so_thu_nhat);
printf("\nType the '5': ");
scanf("%i",Thua_so_thu_hai);
printf(endl"X: %ld",Thua_so_thu_nhat * Thua_so_thu_hai endl);//cout << endl << "X: " << Thua_so_thu_nhat * Thua_so_thu_hai << endl;
}
if (Cau_tra_loi == 2)
{
printf("Type the '1': \n");
scanf("%i",Thua_so_con_lai);
printf("Type the '5': \n");
scanf("%i",Tich);
printf("X: %lf",Tich/Thua_so_con_lai endl);//cout << "X: " << Tich/Thua_so_con_lai << endl;
}
if(Cau_tra_loi<=0 || Cau_tra_loi>=3)
{
printf("\nError: Invailid answer");
}
break;
}
case '/':
{
buoc_tra_loi_phan_4://label /
printf("\nOkey!\nWhat type of 'x'?\nType '1' in case like 4/1=x or '2' in case x/1=4 or '3' 4/x=1\n");
Cau_tra_loi=getch();
if (Cau_tra_loi == 1)
{
printf("\nType the '4': ");
scanf("%i",So_bi_chia);
printf("\nType the '1': ");
scanf("%i",So_chia);
printf(endl"X: %lf",So_bi_chia/So_chia endl);//cout << endl << "X: " << So_bi_chia/So_chia << endl;
}
if (Cau_tra_loi == 2)
{
printf("Type the '1': \n");
scanf("%i",So_chia);
printf("Type the '4': \n");
scanf("%i",Thuong);
printf("X: %ld",So_chia * Thuong);//cout << "X: " << So_chia * Thuong << endl;
}
if (Cau_tra_loi == 3)
{
printf("Type the '4': \n");
scanf("%i",So_bi_chia);
printf("Type the '1': \n");
scanf("%i",Thuong);
printf("X: %%lf",So_bi_chia/Thuong);//cout << "X: " << So_bi_chia/Thuong << endl;
}
if(Cau_tra_loi<=0 || Cau_tra_loi>=4)
{
printf("\nError: Invailid answer");
}
break;
}
default:
{
printf("Error: Invailid answer. To conttinue,press any key!");
break;
}
}
getch();
printf("\nPress any key to end the program!");
exit(0);
}
总是指树列，而不是数据列。因此，请改用 "#0" 并设置 "#1","#2","#3" 以隐藏 树列：
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