如何解决如何在matplotlib中将条形图的xticks居中?
from matplotlib import pyplot as plt
import numpy as np
years = [1901,1911,1921,1931,1941,1951,1961,1971,1981,1991,2001,2011]
population = [237.4,238.4,252.09,251.31,278.98,318.66,361.09,439.23,548.16,683.33,846.42,1028.74]
x = np.arange(len(years)) # the label locations
width = 0.35 # the width of the bars
fig,ax = plt.subplots()
ax.set_ylabel('Population(in million)')
ax.set_title('Years')
ax.set_xticks(x)
ax.set_xticklabels(years)
pps = ax.bar(x - width/2,population,width,label='population')
for p in pps:
height = p.get_height()
ax.annotate('{}'.format(height),xy=(p.get_x() + p.get_width() / 2,height),xytext=(0,3),# 3 points vertical offset
textcoords="offset points",ha='center',va='bottom')
plt.show()
所以,输出变成这样
但是,我刚刚意识到条形图中的 xticks 没有居中
我的问题 - 有人知道如何将 xticks 居中吗?
我试图找到解决方案,但还没有找到
任何帮助将不胜感激,谢谢
解决方法
在 matplotlib
3.4.0 或更新版本中,可以使用 bar_label
代替 annotate
:
import numpy as np
from matplotlib import pyplot as plt
years = [1901,1911,1921,1931,1941,1951,1961,1971,1981,1991,2001,2011]
population = [237.4,238.4,252.09,251.31,278.98,318.66,361.09,439.23,548.16,683.33,846.42,1028.74]
# Create Tick Locations
x = np.arange(len(years))
# Plotting
fig,ax = plt.subplots(figsize=(10,6))
# Do not offset the values of x to center labels (default)
ax.bar(x,population,width=.35,label='population')
# Labels,ticks,etc.
ax.set_ylabel('Population(in million)')
ax.set_title('Years')
ax.set_xticks(x)
ax.set_xticklabels(years)
# Add Bar Labels
for c in ax.containers:
ax.bar_label(c)
plt.show()
,
imo 该教程使绘图变得比需要的更加混乱。您很少需要从绘图上的艺术家那里获取坐标。直接使用您的数据即可:
from matplotlib import pyplot as plt
import numpy as np
years = [1901,1028.74]
x_values = np.arange(len(years))
fig,ax = plt.subplots(figsize=(12,4))
ax.bar(x_values,label='population')
for x,y in zip(x_values,population):
ax.annotate(
str(y),# label is our y-value as a string
xy=(x,y),xytext=(0,3),# 3 points vertical offset
textcoords="offset points",ha='center',va='bottom'
)
ax.set_xticks(x_values)
ax.set_xticklabels(years)
ax.set_ylim(0,1200)
plt.show()
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