在 Python (V. 3.8.1) 中使用 OAuth2 身份验证时如何处理 HTTPError 403？

如何解决在 Python (V. 3.8.1) 中使用 OAuth2 身份验证时如何处理 HTTPError 403？

当尝试使用 Google 搜索控制台 API（特别是 OAuth 2.0）向 Google 搜索控制台查询某些指标（未显示）时，我收到 HTTPError 403：“返回”用户没有足够的权限访问站点“XXXXXXXX”。 com'。另见：https://support.google.com/webmasters/answer/2451999."。详细信息：“[{'message':”用户没有足够的权限访问站点 'https://www.xxxxxx.com'。另请参阅：https://support.google.com/webmasters/answer/2451999.",'domain': 'global','reason': 'forbidden'}]">"（用 x 替换了站点 URL）>

在其他一些尝试中，我也收到了 403 错误，提示我没有 Google Analytics（分析）帐户。

以下是授权访问的代码：

def get_domain_name(start_url):
    domain_name = '{uri.netloc}'.format(uri=urlparse(start_url))  # Get Domain Name To Name Project
    domain_name = domain_name.replace('.','_')
    return domain_name
 
 
def create_project(directory):
    if not os.path.exists(directory):
        print('Create project: '+ directory)
        os.makedirs(directory)


def authorize_creds(creds):
    # Variable parameter that controls the set of resources that the access token permits.
    ScopES = ['https://www.googleapis.com/auth/webmasters.readonly']
 
    # Path to client_secrets.json file
    CLIENT_SECRETS_PATH = creds
 
    # Create a parser to be able to open browser for Authorization
    parser = argparse.ArgumentParser(
        formatter_class=argparse.RawDescriptionHelpformatter,parents=[tools.argparser])
    flags = parser.parse_args([])
 
    flow = client.flow_from_clientsecrets(
        CLIENT_SECRETS_PATH,scope = ScopES,message = tools.message_if_missing(CLIENT_SECRETS_PATH))
 
    # Prepare credentials and authorize HTTP
    # If they exist,get them from the storage object
    # credentials will get written back to a file.
    storage = file.Storage('authorizedcreds.dat')
    credentials = storage.get()
 
    # If authenticated credentials don't exist,open browser to authenticate
    if credentials is None or credentials.invalid:
        credentials = tools.run_flow(flow,storage,flags)
    http = credentials.authorize(http=httplib2.Http())
    webmasters_service = build('webmasters','v3',http=http)
    return webmasters_service