如何解决打印算术平均值，最小和最大年龄
这个 Python 程序应该读取出生年份，直到输入数字零。
然后程序应该打印出平均年龄以及最小和最大的年龄。
我需要两件事的帮助。
- 当输入年份为 -N 时打印“年龄不合理，请再试一次”，例如“-45”
- 在我退出循环时打印结果，即算术平均值、最年轻和最老的仅。 这意味着当我输入 0 时。
当前输出：
Please type in birth year,to stop,enter 0: 1948
Average age is 72.0 years old.
The younges is 72 years old,and the oldest is 72 years old.
Please type in birth year,enter 0: 1845
Unreasonable age,please try again
Average age is 72.0 years old.
The younges is 72 years old,enter 0: 1995
Average age is 48.5 years old.
The younges is 25 years old,enter 0: 2005
Average age is 37.333333333333336 years old.
The younges is 15 years old,enter 0: 0
Average age is 37.333333333333336 years old.
The youngest is 15 years old,and the oldest is 72 years old.
我想要的预期输出：
Please type in birth year,enter 0.
Year: 1998
Year: 1932
Year: 1887
Fail: Unreasonable age,please try again.
Year: 1987
Year: -77
Fail: Unreasonable age,please try again.
Year: 1963
Year: 0
Average age is 49 years old. The youngest is 21 years old,and the oldest is 87 years old.
示例代码：
# set number_years to zero ### Initial value (has not started counting yet)
number_year = 0
# set number_years to zero ### Initial value (has not started counting yet)
sum_year = 0
# set sum_year to zero ### No maximum age yet
max_year = 0
# set max_year to zero ### Well increased minimum value (age) to start with
min_year = 110
# set input_year to minus 1 ### Only as start value for the sake of the loop start!
input_year = -1
# White input_year is not 0:
while input_year != 0:
# print info and store input value to input_year,stop if 0 is entered
input_year = int(input("Please type in birth year,enter 0: "))
# let age be (2020 - input_year)
age = (2020 - input_year)
# To avoid beauty flaws with the printout "Unreasonable year ..."
# when the final zero is entered,we must check that age is not 2020
# which it is deceptive enough because 2020-0=2020
# if age is less than zero or age is greater than 110 and age is not 2020:
if age < 0 or age > 110 and age != 2020:
# Print "Unreasonable age,please try again"
print("Unreasonable age,please try again")
# else
else:
# if input_year is greater than zero:
if input_year > 0:
# increase number_year with 1
number_year += 1
# let sum_year become sum_year + age
sum_year = sum_year + age
# if age is less than min_year:
if age < min_year:
# set min_year to age ### New minimum age found
min_year = age
# if age is bigger than max_year:
if age > max_year:
# set max_year to age ### New maximum age found
max_year = age
## If the entered number was 0,exit the loop
#if input_year == 0:
# break
# Now just print the arithmetic average,the youngest and oldest
# Print "Average age is ",sum_year / number_year,"year."
print("Average age is ","years old.")
# Print "The younges is ",min_year," and the oldest is ",max_year
print("The youngest is","years old,",max_year,"years old.")
# Done! :-)
解决方法
代码的工作原理是简单地取消最后两个打印语句的缩进并取消对 if …: break 的注释：
# Initial value (has not started counting yet)
number_year = 0
# Initial value (has not started counting yet)
sum_year = 0
# No maximum age yet
max_year = 0
# Well increased minimum value (age) to start with
min_year = 110
# Only as start value for the sake of the loop start!
input_year = -1
while input_year != 0:
# print info and store input value to input_year,stop if 0 is entered
input_year = int(input("Please type in birth year,to stop,enter 0: "))
age = 2020 - input_year
# To avoid beauty flaws with the printout "Unreasonable year ..."
# when the final zero is entered,we must check that age is not 2020
# which it is deceptive enough because 2020-0=2020
if age < 0 or age > 110 and age != 2020:
print("Unreasonable age,please try again")
# else
else:
if input_year > 0:
number_year += 1
sum_year += age
if age < min_year:
### New minimum age found
min_year = age
if age > max_year:
### New maximum age found
max_year = age
if input_year == 0:
break
# print the arithmetic average,the youngest and oldest
print("Average age is ",sum_year / number_year,"years old.")
print("The youngest is",min_year,"years old,"," and the oldest is ",max_year,"years old.")
我还删除了不必要的评论。但是，只需使用列表就可以大大简化您的代码：
ages = []
while True: # infinite loop - we will exit by break-ing when age is 0
age = 2020 - int(input("Please enter birth year (0 to exit)"))
if age == 2020: # user entered a 0 - exit loop
break
if age < 0 or age > 110:
print("Unreasonable age,please try again")
continue # directly go to next loop
ages.append(age) # will only get appended if the condition above was false because of the continue
if ages: # ages list is not empty
print("Average age is",sum(ages) / len(ages),"years old")
print("The youngest is",min(ages),"old,and the oldest is",max(ages),"old")
else:
print("No ages entered - cannot print mean,min and max age - exiting")
您可以将所有年龄存储在一个列表中，然后根据需要进行数学计算。
# initialize your list
ages = []
# run your code here,adding the age value with each valid input
# this can be done right before finishing the loop,after the last if statement
...
while input_year != 0:
...
ages.append(age)
# at the end,do the required calculations
average_age = np.mean(ages)
min_age = np.min(ages)
max_age = np.max(ages)
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