如何解决向 Flask API 发送 Post 请求,但未接收数据
所以我试图将某些值发送到我的 Flask API streamlit 应用程序,但它似乎没有执行发布请求。现在,我的 main.py
的发布请求代码不起作用,因为我收到了 TypeError: 'nonetype'
。
app.py:
import requests
import json
import streamlit as st
...
api_url = "http://127.0.0.1:5000/" # Flask url
create_row_data = {'name': name,'type': get_type(name),'token_value': token_value,'external': external,'start': start,'end': end,'step': step}
print(create_row_data)
# The terminal cannot print out the value of r and it appears that it cannot send the post request as well
r = requests.post(url=api_url,json = create_row_data)
print(r)
app.py 中 print(create_row_data)
的输出:
{'name': 'session','type': 'area_chart','token_value': 'G0as7vjk1ksuxn94','external': False,'start': datetime.datetime(2021,7,1,14,9,322438),'end': datetime.datetime(2021,8,322441),'step': '1d'}
main.py:
from flask import Flask
from flask import jsonify
from flask import request
...
import requests,json
@app.route('/',methods=['GET','POST'])
def get_data():
if request.method == 'GET':
return "ok",200
if request.method =='POST':
p_name = request.json['name']
p_type = request.json['type']
...
p_end = request.json['end']
p_step = request.json['step']
create_row_data = {'p_name': str(p_name),'p_type': str(p_type),...,'p_end': str(p_end),'p_step': str(p_step)}
print(create_row_data)
response = requests.post(url,data=json.dumps(create_row_data),headers= {'Content-type': 'application/json'}
return response.content
解决方法
据我了解,您需要将数据发布到 127.0.0.1 并对其进行处理以从 app.py 创建表,使用 flask_restful 创建 API 端点,以便您可以发布数据。 main.py 的代码是:
from flask import Flask
from flask import Flask,request
from flask_restful import Resource,Api
from flask import jsonify
from flask import request
import requests,json
app = Flask(__name__)
api = Api(app)
@app.route('/',methods=['GET','POST'])
def get_data():
if request.method == 'GET':
return "ok",200
class create_row_data(Resource):
def post(self):
response = request.get_json()
p_name = response['name']
p_type = response['type']
...
# code to process your data and to create a table
# return something for your client application
return True
api.add_resource(create_row_data,'/create_row_data/')
的 url 之外,您的客户端 app.py 不需要任何更改版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。