SCRAPY 使用 Xpath 表达式抓取 imdb 网站

如何解决SCRAPY 使用 Xpath 表达式抓取 imdb 网站

在输出中获取所有内容 无法找出代码中的问题

抓取 imdb 上评分最高的 1000 部电影的详细信息

链接：- https://www.imdb.com/search/title/?count=100&groups=top_1000&sort=user_rating

代码

# -*- coding: utf-8 -*-
import scrapy
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import CrawlSpider,Rule


class BestMoviesspider(CrawlSpider):
    name = 'best_movies'
    allowed_domains = ['imdb.com']
    start_urls = ['https://www.imdb.com/search/title/?count=100&groups=top_1000&sort=user_rating']
    
    rules = (
        Rule(LinkExtractor(restrict_xpaths="//h3[@class='lister-item-header']/a "),callback='parse_item',follow=True),)

    def parse_item(self,response):
        yield{
            'title' : response.xpath("//h1[@class='TitleHeader__TitleText-sc-1wu6n3d-0 cLNRlG']/text()").get(),'year' : response.xpath("(//li/span[@class='TitleBlockMetaData__ListItemText-sc-12ein40-2 jedhex'])[1]/text()").get(),'duration' : response.xpath("(//li[@class='ipc-inline-list__item'])[3]/text()").get(),'rating' : response.xpath("(//span[@class='AggregateratingButton__ratingscore-sc-1il8omz-1 fhMjqK'])[2]/text()").get(),'director' : response.xpath("(//a[@class='ipc-Metadata-list-item__list-content-item ipc-Metadata-list-item__list-content-item--link'])[13]/text()").get(),'movie_url' : response.url
        }
        
        

解决方法

您项目的 xpath 选择几乎完全不正确，并且没有分页规则。这是完整的解决方案。您还将从我的解决方案中了解到很酷的事情是如何进行 CrawlSpider 分页。

import scrapy
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import CrawlSpider,Rule


class BestMoviesSpider(CrawlSpider):
    name = 'best_movies'
    allowed_domains = ['imdb.com']
    start_urls = ['https://www.imdb.com/search/title/?count=100&groups=top_1000&sort=user_rating']
    
    rules = (
        Rule(LinkExtractor(restrict_xpaths="//h3[@class='lister-item-header']/a "),callback='parse_item',follow=False),Rule(LinkExtractor(restrict_xpaths='(//*[@class="lister-page-next next-page"])[1]'),follow=True),)

    def parse_item(self,response):
        yield{
            'title' : response.xpath('(//h1/text())[1]').get().strip(),'year' : response.xpath('//span[@id="titleYear"]/a/text()').get(),'duration' : response.xpath('normalize-space((//time/text())[1])').get(),'rating' : response.xpath('//*[@itemprop="ratingValue"]/text()').get(),'director' : response.xpath('(//*[@class="credit_summary_item"]/h4/following-sibling::a)[1]/text()').get(),'movie_url' : response.url
        }