如何确定是否选择了 switch case？

如何解决如何确定是否选择了 switch case？

我有一个正在处理的项目，它要求我有一个大小设置为 5 的数组。然后我需要从 4 个不同的案例中收集数据，并将它们存储 5 次。 （其中一个案例可以多次使用，案例由用户输入指定）。这是我尝试过的：

for (count = 0; count < 5; count++) {
     employeeTypestring = JOptionPane.showInputDialog(null,"What type of employee are you?\n\nEnter the number that corresponds to your answer.\n1. Salaried\n2. Hourly\n3. Commissioned\n4. Base Plus Commissioned","Employee Type",JOptionPane.QUESTION_MESSAGE);
     employeeType = Integer.parseInt(employeeTypestring);

     switch (employeeType) {
        case 1:
           firstName = JOptionPane.showInputDialog(null,"What is your first name?","First Name",JOptionPane.QUESTION_MESSAGE);
           lastName = JOptionPane.showInputDialog(null,"What is your last name?","Last Name",JOptionPane.QUESTION_MESSAGE);
           ssn = JOptionPane.showInputDialog(null,"What is your social security number?","SSN",JOptionPane.QUESTION_MESSAGE);
           salaryString = JOptionPane.showInputDialog(null,"What is your weekly salary?","Salary",JOptionPane.QUESTION_MESSAGE);
           salary = Double.parseDouble(salaryString);
           break;

        case 2:
           firstName = JOptionPane.showInputDialog(null,JOptionPane.QUESTION_MESSAGE);
           wageString = JOptionPane.showInputDialog(null,"What is your hourly wage?","Hourly Wage",JOptionPane.QUESTION_MESSAGE);
           wage = Double.parseDouble(wageString);
           houRSString = JOptionPane.showInputDialog(null,"How many hours per week do you work?","Hours Worked",JOptionPane.QUESTION_MESSAGE);
           hours = Integer.parseInt(houRSString);
           break;

        case 3:
           firstName = JOptionPane.showInputDialog(null,JOptionPane.QUESTION_MESSAGE);
           salesstring = JOptionPane.showInputDialog(null,"What are your weekly gross sales?","Gross Sales",JOptionPane.QUESTION_MESSAGE);
           sales = Double.parseDouble(salesstring);
           rateString = JOptionPane.showInputDialog(null,"What percent of commission do you receive?","Commsission Rate",JOptionPane.QUESTION_MESSAGE);
           rate = Double.parseDouble(rateString);
           break;

        case 4:
           firstName = JOptionPane.showInputDialog(null,JOptionPane.QUESTION_MESSAGE);
           rate = Double.parseDouble(rateString);
           salaryString = JOptionPane.showInputDialog(null,"What is your base pay?","Base Pay",JOptionPane.QUESTION_MESSAGE);
           salary = Double.parseDouble(salaryString);
           break;

        default:
           JOptionPane.showMessageDialog(null,"Invalid entry!","Error",JOptionPane.ERROR_MESSAGE);
           break;
     }
     switch (count) {
        case 0:
           employees[0] = new SalariedEmployee(firstName,lastName,ssn,salary);
           break;
        case 1:
           employees[1] = new HourlyEmployee(firstName,wage,hours);
           break;
        case 2:
           employees[2] = new CommissionEmployee(firstName,sales,rate);
           break;
        case 3:
           employees[3] = new BasePlusCommissionEmployee(firstName,rate,salary);
           break;
        case 4:
           employees[4] = new SalariedEmployee(firstName,salary);
     }
  }

我计划用其他东西替换最后一个 Switch(count)，但不知道如何去做。我遇到的问题是，无论我输入什么， Switch(count) 都会迭代到下一个，而不关心我选择了什么。因此，如果我选择员工类型 1，然后选择员工类型 3，它会询问我类型 3 的信息，但显示类型 2 的所有信息（导致空白结果）。

salaried employee: john smith
social security number: 111-11-1111
date of birth: null
weekly salary: $800.00
earned $3,200.00

hourly employee: sue jones
social security number: 222-22-2222
date of birth: null
hourly wage: $0.00; hours worked: 0.00
earned $0.00

commission employee: karen price
social security number: 333-33-3333
date of birth: null
gross sales: $10,000.00; commission rate: 0.06
earned $2,400.00

base-salaried commission employee: bob lewis
social security number: 444-44-4444
date of birth: null
gross sales: $5,000.00; commission rate: 0.04; base salary: $300.00
new base salary with 10% increase is: $330.00
earned $2,120.00

salaried employee: jomes allen
date of birth: null
weekly salary: $300.00
earned $1,200.00

Employee 0 is a SalariedEmployee
Employee 1 is a HourlyEmployee
Employee 2 is a CommissionEmployee
Employee 3 is a BasePlusCommissionEmployee
Employee 4 is a SalariedEmployee

如上所示，输出显示的是薪水、小时、佣金、BasePlus，然后是薪水员工，当我实际输入薪水时，然后又是薪水。

解决方法

如果我理解正确，这应该可行：

for (count = 0; count < 5; count++) {
     employeeTypeString = JOptionPane.showInputDialog(null,"What type of employee are you?\n\nEnter the number that corresponds to your answer.\n1. Salaried\n2. Hourly\n3. Commissioned\n4. Base Plus Commissioned","Employee Type",JOptionPane.QUESTION_MESSAGE);
     employeeType = Integer.parseInt(employeeTypeString);

     switch (employeeType) {
        case 1:
           // input data (removed for brevity)
           employees[count] = new SalariedEmployee(firstName,lastName,ssn,salary);
           break;

        case 2:
           // input data (removed for brevity)
           employees[count] = new HourlyEmployee(firstName,wage,hours);
           break;

        case 3:
           // input data (removed for brevity)
           employees[count] = new CommissionEmployee(firstName,sales,rate);
           hours);
           break;

        case 4:
           // input data (removed for brevity)
           employees[count] = new BasePlusCommissionEmployee(firstName,rate,salary);
           break;

        default:
           JOptionPane.showMessageDialog(null,"Invalid entry!","Error",JOptionPane.ERROR_MESSAGE);
           count--;   // Subtract 1 so the loop repeats
           break;
     }
  }

,

可能值得将 EmployeeType 封装为单独的实体类/枚举返回值以创建/返回创建的员工对象。