如何解决python的NSIS错误说：无法执行脚本
所以我试图使用 NSIS 创建一个 python 可执行文件，当我启动它时，它给了我以下错误：
这些是我的设置：
这是我的代码：
# import pygame library
import pygame
# initialise the pygame font
pygame.font.init()
# Total window
screen = pygame.display.set_mode((500,600))
# Title and Icon
pygame.display.set_caption("SUDOKU SOLVER")
#a = pygame.image.load('icon.ico')
#pygame.display.set_icon(a)
x = 0
y = 0
dif = 500 / 9
val = 0
# Default Sudoku Board.
grid =[
[7,8,4,1,2,0],[6,7,5,9],[0,6,8],9,3,[9,5],2],[1,7]
]
# Load test fonts for future use
font1 = pygame.font.SysFont("comicsans",40)
font2 = pygame.font.SysFont("comicsans",20)
def get_cord(pos):
global x
x = pos[0]//dif
global y
y = pos[1]//dif
# Highlight the cell selected
def draw_Box():
for i in range(2):
pygame.draw.line(screen,(255,0),(x * dif-3,(y + i)*dif),(x * dif + dif + 3,7)
pygame.draw.line(screen,( (x + i)* dif,y * dif ),((x + i) * dif,y * dif + dif),7)
# Function to draw required lines for making Sudoku grid
def draw():
# Draw the lines
for i in range (9):
for j in range (9):
if grid[i][j]!= 0:
# Fill blue color in already numbered grid
pygame.draw.rect(screen,(0,153,153),(i * dif,j * dif,dif + 1,dif + 1))
# Fill gird with default numbers specified
text1 = font1.render(str(grid[i][j]),0))
screen.blit(text1,(i * dif + 15,j * dif + 15))
# Draw lines horizontally and verticallyto form grid
for i in range(10):
if i % 3 == 0 :
thick = 7
else:
thick = 1
pygame.draw.line(screen,i * dif),(500,thick)
pygame.draw.line(screen,500),thick)
# Fill value entered in cell
def draw_val(val):
text1 = font1.render(str(val),0))
screen.blit(text1,(x * dif + 15,y * dif + 15))
# Raise error when wrong value entered
def raise_error1():
text1 = font1.render("WRONG !!!",(20,570))
def raise_error2():
text1 = font1.render("Wrong !!! Not a valid Key",570))
# Check if the value entered in board is valid
def valid(m,i,j,val):
for it in range(9):
if m[i][it]== val:
return False
if m[it][j]== val:
return False
it = i//3
jt = j//3
for i in range(it * 3,it * 3 + 3):
for j in range (jt * 3,jt * 3 + 3):
if m[i][j]== val:
return False
return True
# Solves the sudoku board using Backtracking Algorithm
def solve(grid,j):
while grid[i][j]!= 0:
if i<8:
i+= 1
elif i == 8 and j<8:
i = 0
j+= 1
elif i == 8 and j == 8:
return True
pygame.event.pump()
for it in range(1,10):
if valid(grid,it)== True:
grid[i][j]= it
global x,y
x = i
y = j
# white color background\
screen.fill((255,255,255))
draw()
draw_Box()
pygame.display.update()
pygame.time.delay(20)
if solve(grid,j)== 1:
return True
else:
grid[i][j]= 0
# white color background\
screen.fill((255,255))
draw()
draw_Box()
pygame.display.update()
pygame.time.delay(50)
return False
# display instruction for the game
def instruction():
text1 = font2.render("PRESS D TO RESET TO DEFAULT / R TO EMPTY",0))
text2 = font2.render("ENTER VALUES AND PRESS ENTER TO VISUALIZE",520))
screen.blit(text2,540))
# display options when solved
def result():
text1 = font1.render("FINISHED PRESS R or D",570))
run = True
flag1 = 0
flag2 = 0
rs = 0
error = 0
# The loop thats keep the window running
while run:
# White color background
screen.fill((255,255))
# Loop through the events stored in event.get()
for event in pygame.event.get():
# Quit the game window
if event.type == pygame.QUIT:
run = False
# Get the mouse postion to insert number
if event.type == pygame.MOUSEBUTTONDOWN:
flag1 = 1
pos = pygame.mouse.get_pos()
get_cord(pos)
# Get the number to be inserted if key pressed
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x-= 1
flag1 = 1
if event.key == pygame.K_RIGHT:
x+= 1
flag1 = 1
if event.key == pygame.K_UP:
y-= 1
flag1 = 1
if event.key == pygame.K_DOWN:
y+= 1
flag1 = 1
if event.key == pygame.K_1:
val = 1
if event.key == pygame.K_2:
val = 2
if event.key == pygame.K_3:
val = 3
if event.key == pygame.K_4:
val = 4
if event.key == pygame.K_5:
val = 5
if event.key == pygame.K_6:
val = 6
if event.key == pygame.K_7:
val = 7
if event.key == pygame.K_8:
val = 8
if event.key == pygame.K_9:
val = 9
if event.key == pygame.K_RETURN:
flag2 = 1
# If R pressed clear the sudoku board
if event.key == pygame.K_r:
rs = 0
error = 0
flag2 = 0
grid =[
[0,0]
]
# If D is pressed reset the board to default
if event.key == pygame.K_d:
rs = 0
error = 0
flag2 = 0
grid =[
[7,7]
]
if flag2 == 1:
if solve(grid,0)== False:
error = 1
else:
rs = 1
flag2 = 0
if val != 0:
draw_val(val)
# print(x)
# print(y)
if valid(grid,int(x),int(y),val)== True:
grid[int(x)][int(y)]= val
flag1 = 0
else:
grid[int(x)][int(y)]= 0
raise_error2()
val = 0
if error == 1:
raise_error1()
if rs == 1:
result()
draw()
if flag1 == 1:
draw_Box()
instruction()
# Update window
pygame.display.update()
# Quit pygame window
pygame.quit()
它应该是这样工作的：
解决方法
pygame.font.SysFont 不适用于使用 PyInstaller 创建的 .exe 文件。改用 pygame.font.Font。
对于Comic Sans MS，您可以下载它here。然后只需复制与 .ttf 文件位于同一目录中的 .exe 文件之一并使用如下代码：
font1 = pygame.font.Font('ComicSansMS3.ttf',40)
总之，如果你想验证错误是什么，自己显示出来；在转换文件之前，像这样编辑它：
from tkinter.messagebox import showerror
try:
# your entire code here
except Exception as error:
showerror('Error detected',error)
这样错误就会以这样的消息框的形式显示：
关于错误 here 的更多信息。
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