尝试在 Laravel 中播种表时出错

如何解决尝试在 Laravel 中播种表时出错

当我尝试执行 PHP artisan migrate:fresh --seed 命令时出现错误。我不明白它们是怎么回事，我不知道是什么导致了它们。问题描述如下。

工厂文件 PostFactory.PHP:

<?PHP

namespace Database\Factories;

use App\Models\Post;
use Illuminate\Database\Eloquent\Factories\Factory;

class PostFactory extends Factory
{
    /**
     * The name of the factory's corresponding model.
     *
     * @var string
     */
    protected $model = Post::class;

    /**
     * Define the model's default state.
     *
     * @return array
     */
    public function deFinition()
    {
        $title = $faker->realText(rand(10,40));
        $short_title = \Illuminate\Support\Str::length($title) > 30 ? mb_substr($title,30) . "..." : $title;
        $created = $faker->dateTimeBetween("-30days","-1days");

        return [
            "title" => $title,"short_title" => $short_title,"author_id" => rand(1,4),"descr" => $faker->realText(100,500),"created_at" => $created,"updated_at" => $created
        ];
    }
}

DatabaseSeeder.PHP:

<?PHP

namespace Database\Seeders;

use Illuminate\Database\Seeder;

class DatabaseSeeder extends Seeder
{
    /**
     * Seed the application's database.
     *
     * @return void
     */
    public function run()
    {
        \App\Models\User::factory()->count(4)->create();
        \App\Models\Post::factory()->count(15)->create();
    }
}

当我执行 PHP artisan migrate:fresh --seed 时出现这些错误：

Illuminate\Database\QueryException 

  sqlSTATE[HY000] [2002],..      .
 (sql: SHOW FULL TABLES WHERE table_type = 'BASE TABLE')

  at C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connection.PHP:692
    688▕         // If an exception occurs when attempting to run a query,we'll format the error
    689▕         // message to include the bindings with sql,which will make this exception a   
    690▕         // lot more helpful to the developer instead of just the database's errors.     
   Illuminate\Database\QueryException 

  sqlSTATE[HY000] [2002],which will make this exception a
    690▕         // lot more helpful to the developer instead of just the database's errors.
    691▕         catch (Exception $e) {
  ➜ 692▕             throw new QueryException(
    693▕                 $query,$this->prepareBindings($bindings),$e
    694▕             );
    695▕         }
    696▕

  1   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.PHP:70
      PDOException::("sqlSTATE[HY000] [2002],..      .
")

  2   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.PHP:70
      PDO::__construct("MysqL:host=localhost;port=3306;dbname=laralove","root","",[])

我已经检查了错误描述中提供的文件中的行，但我不知道是什么导致了错误。

任何帮助都会非常感谢

UPD 0：

我尝试按照@Rwd 的建议将配置文件中的“localhost”更改为“127.0.0.1”。之前的错误都消失了。但现在我遇到了其他错误：

ErrorException 

  Undefined variable: faker

  at C:\xampp\htdocs\laralove\database\factories\PostFactory.PHP:24
     20▕      * @return array
     21▕      */
     22▕     public function deFinition()
     23▕     {
  ➜  24▕         $title = $faker->realText(rand(10,40));
     25▕         $short_title = \Illuminate\Support\Str::length($title) > 30 ? mb_substr($title,30) . "..." : $title;
     26▕         $created = $faker->dateTimeBetween("-30days","-1days");
     27▕
     28▕         return [

  1   C:\xampp\htdocs\laralove\database\factories\PostFactory.PHP:24
      Illuminate\Foundation\Bootstrap\HandleExceptions::handleError("Undefined variable: faker","C:\xampp\htdocs\laralove\database\factories\PostFactory.PHP",[])

  2   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Eloquent\Factories\Factory.PHP:385
      Database\Factories\PostFactory::deFinition()

UPD 1：

按照@Cristea 的建议将 $faker 替换为 $this->faker，现在得到了以前的错误：

  1   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.PHP:70
      PDOException::("sqlSTATE[HY000] [2002],[])

如@Rwd 建议的那样，在 .env 和 database.PHP 中 localhost 仍更改为 127.0.0.1

解决方法

只需将 $faker 替换为 $this->faker