如何解决SPAQRL 创建排除查询
我有这种结构
<ontology:Louvre>
<rdf:type ontology:Museum/>
<ontology:preserves rdf:Gioconda/>
<ontology:locatedIn rdf:Paris/>
<ontology:name>Louvre</ontology:name>
<ontology:Gioconda>
<rdf:type ontology:Artwork/>
<ontology:preserved rdf:Louvre/>
<ontology:author rdf:Leonardo/>
<nomeOpera>Gioconda</nomeOpera>
<rdf:Leonardo_Da_Vinci>
<rdf:type ontology:Painter"/>
<ontology:paint ontology:Gioconda"/>
<ontology:paint ontology:Ultima_cena"/>
<name>Leonardo Da Vinci</name>
...(other museum,artist and artwork)
I use "ontology" to indicate my prefix
有没有可能找回博物馆的独家艺术家?
解决方法
我找到了解决方案。 这是我正在寻找的查询
SELECT DISTINCT * WHERE {
?museum ontology:preserves ?artwork .
?museum ontology:name "Louvre" .
?artwork ontology:author ?author.
FILTER NOT EXISTS{
?museum2 ontology:preserves ?artwork2 .
?artwork2 ontology:author ?author .
FILTER (?museum2 != ?museum)
}
}
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