控制直方图的facecolor

如何解决控制直方图的facecolor

在下面的直方图中，

import numpy as np
import matplotlib.pyplot as plt
tinter = [0.8253909999999998,0.8804020000000001,0.14202099999999973,0.7727520000000005,1.1040220000000005,0.10714699999999944,0.5750040000000016,0.7876929999999973,0.8980040000000002,1.1478490000000008,0.44635099999999994,1.052067000000001,0.4327469999999991,0.3272960000000005,0.26918099999999967,0.3854459999999982,0.1827140000000007,0.8867760000000011,0.7774879999999982,0.21082900000000038,0.6758939999999996,0.4335760000000022,0.6791699999999992,0.7758439999999993,0.15755200000000258,0.1414289999999987,0.36975599999999886,0.8993549999999999,0.6577640000000002,1.043728999999999,0.19952800000000082,0.12645200000000045,0.3454990000000002,0.9054520000000004,0.7165229999999987,0.9425269999999983,0.7159280000000052,0.7413279999999958,0.12669900000000212,0.2822880000000012,0.3690029999999993,0.7246340000000018,0.4718329999999966,0.7580859999999987,0.744059,0.19344999999999857,0.12031900000000206,0.47543600000000197,0.437542999999998,0.44232000000000227,0.5250109999999992,0.17673200000000122,0.2440649999999991,0.31524799999999686,0.7674680000000009,0.7837700000000041,1.1910290000000003,0.14404899999999543,0.21560399999999902,0.19931500000000568,0.27113699999999596,0.728234999999998,0.5061920000000057,0.6459329999999994,0.7817450000000008,0.8265129999999985,0.17931199999999592,0.30208600000000274,0.32583699999999993,0.41771599999999864]
n,bins,patches = plt.hist(x=tinter,bins='auto',color='#0504aa',alpha=0.7,rwidth=0.9,)
plt.grid(axis='y',alpha=0.35)
plt.xlabel('time [s]')
plt.ylabel('Frequency')
plt.title('Hit interval')

我想为直方图的条形设置两种不同的颜色。 有一个先例问题（这个 link），但解决方案将条形的颜色设置在一个范围内，例如，一种颜色的 0 到 3 条形。

这是一个不同的问题，因为我想区分直方图中的两个区域。我不知道特定的直方图如何以及有多少条。 在上面的例子中，颜色的分离应该是 0.6：时间的左边=一种颜色的 0.6 秒，时间的右边=另一种颜色的 0.6。 如果无法制作两种颜色的条形（在示例中，条形中覆盖了一系列时间值，包括 0.6），则颜色的分离应从示例中的最低条开始（时间条=0.2 ) 到包含的时间条 = 0.6。并且，在示例中，是另一种颜色的最后四个柱（时间 = 0.6 秒以上）。

例如，在这个例子中，给出 'plt.hist()` 的 n 和 bins 的值是：

n = array([16.,11.,10.,3.,16.,8.,3.])
bins=array([0.107147,0.24263225,0.3781175,0.51360275,0.649088,0.78457325,0.9200585,1.05554375,1.191029  ])

我想要带有 n 16,11,10 和 3 的条形，其颜色与另一组带有 n 16,8,3,3 的条形不同，并将其用于一般直方图。

解决方法

您可以遍历条形并测试它是否完全位于分隔的右侧、完全位于左侧或交叉。您相应地更改栏的颜色。

当条形穿过分隔符时，条形获得左侧区域的颜色，并且其尺寸变窄以接触分隔符。可以添加栏的副本，并移动右侧区域的颜色及其 x 位置。

import matplotlib.pyplot as plt
import numpy as np
from copy import copy

tinter = [0.82539,0.8804,0.14202,0.77275,1.10402,0.10715,0.575,0.78769,0.898,1.14785,0.44635,1.05207,0.43275,0.3273,0.26918,0.38545,0.18271,0.88678,0.77749,0.21083,0.67589,0.43358,0.67917,0.77584,0.15755,0.14143,0.36976,0.89935,0.65776,1.04373,0.19953,0.12645,0.3455,0.90545,0.71652,0.94253,0.71593,0.74133,0.1267,0.28229,0.369,0.72463,0.47183,0.75809,0.74406,0.19345,0.12032,0.47544,0.43754,0.44232,0.52501,0.17673,0.24406,0.31525,0.76747,0.78377,1.19103,0.14405,0.2156,0.19932,0.27114,0.72823,0.50619,0.64593,0.78175,0.82651,0.17931,0.30209,0.32584,0.41772]
n,bins,patches = plt.hist(x=tinter,bins='auto',color='#0504aa',alpha=0.7,rwidth=0.9)
plt.grid(axis='y',alpha=0.35)
plt.xlabel('time [s]')
plt.ylabel('Frequency')
plt.title('Hit interval')
separator = 0.6
left_color = 'turquoise'
right_color = 'tomato'
for bar in patches:
    x,y = bar.get_xy()
    w = bar.get_width()
    if x > separator:
        bar.set_color(right_color)
    else:
        bar.set_color(left_color)
        if x + w > separator:
            bar.set_width(separator-x)
            new_bar = copy(bar)
            new_bar.set_x(separator)
            new_bar.set_width(x+w-separator)
            new_bar.set_color(right_color)
            plt.gca().add_patch(new_bar)
plt.show()

如果您希望包含分隔符值的完整条为一种颜色，则可以省略 if x + w > separator: 下方的块。

n,y = bar.get_xy()
    w = bar.get_width()
    if x > separator:
        bar.set_color(right_color)
    else:
        bar.set_color(left_color)
plt.show()