过去 12 个月的 MS Access SQL 重新排序日期

如何解决过去 12 个月的 MS Access SQL 重新排序日期

我正在尝试正确设置查询格式，以使 Access 365 图表能够正常工作（我知道，我知道），用于跟踪 12 个月的图表。 IE。如果我在 6 月运行此查询，我希望 6 月是最后一个数据点（第 12 个月），并按顺序向后返回到前一个 7 月（第 1 个月）。我在如何将这个逻辑构建到查询中陷入困境，因为顺序是不变的，但相对数量会发生变化。我有：

FROM (
SELECT "Jan" as Mo,Month(DateAdd("m",1,Date())) AS MoN,SUM(IIF(MonthNumOpen = 1,0)) AS             SalesOpened,SUM(IIF(MonthNumClose = 1,0)) AS Sales,Month(Date()) as Today1,Sales - SalesOpened as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Feb",2,Date())),SUM(IIF(MonthNumOpen = 2,0)) AS SalesOpened,SUM(IIF(MonthNumClose = 2,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Mar",3,SUM(IIF(MonthNumOpen = 3,SUM(IIF(MonthNumClose = 3,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Apr",4,SUM(IIF(MonthNumOpen = 4,SUM(IIF(MonthNumClose = 4,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "May",5,SUM(IIF(MonthNumOpen = 5,SUM(IIF(MonthNumClose = 5,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Jun",6,SUM(IIF(MonthNumOpen = 6,SUM(IIF(MonthNumClose = 6,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Jul",7,SUM(IIF(MonthNumOpen = 7,SUM(IIF(MonthNumClose = 7,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Aug",8,SUM(IIF(MonthNumOpen = 8,SUM(IIF(MonthNumClose = 8,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Sep",9,SUM(IIF(MonthNumOpen = 9,SUM(IIF(MonthNumClose = 9,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Oct",10,SUM(IIF(MonthNumOpen = 10,SUM(IIF(MonthNumClose = 10,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Nov",11,SUM(IIF(MonthNumOpen = 11,SUM(IIF(MonthNumClose = 11,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
UNION SELECT "Dec",12,SUM(IIF(MonthNumOpen = 12,SUM(IIF(MonthNumClose = 12,Sales - SalesOpened  as SalesDelta FROM Trailing12MonthData_Trial1
ORDER BY MoN
)  AS subquery
ORDER BY IIF(Month(Date()) = 11,Mo ="Jan",IIF(Month(Date()) = 10,Mo="Feb",IIF(Month(Date()) = 9,Mo="Mar",IIF(Month(Date()) = 8,Mo="Apr",IIF(Month(Date()) = 7,Mo="May",IIF(Month(Date()) = 6,Mo="Jun",IIF(Month(Date()) = 5,Mo="Jul",IIF(Month(Date()) = 4,Mo="Aug",IIF(Month(Date()) = 3,Mo="Sep",IIF(Month(Date()) = 2,Mo="Oct",IIF(Month(Date()) = 1,Mo="Nov",Mo="Dec"))))))))))),MoN;

非常感谢您的帮助。

解决方法

使用模数来计算每个月的周期。这里六月是当前月份：

For M = 1 to 12 : ? "Period: " & M,"Month: " & (Month(Date) - 1 + M) Mod 12 + 1 : Next
Period: 1     Month: 7
Period: 2     Month: 8
Period: 3     Month: 9
Period: 4     Month: 10
Period: 5     Month: 11
Period: 6     Month: 12
Period: 7     Month: 1
Period: 8     Month: 2
Period: 9     Month: 3
Period: 10    Month: 4
Period: 11    Month: 5
Period: 12    Month: 6

那么你可能可以大大减少这个查询。