mysql jsonarrayagg 用于逗号分隔的 id

如何解决mysql jsonarrayagg 用于逗号分隔的 id

我有两个表 casetemp 和 medication_master

患者有字段

id	名称	年龄	性别	medicineid
1	xyz	23	M	1,2
2	abc	20	f	3

医学有领域

id	medname	desc
1	crosin	发烧标签
2	etzaa	洗发水
3	zaanta	止痛药

我希望 MysqL 左连接输出如下：

[{
  "id":"1","name":"xyz","age":"23","sex":"M","medicine_id":"1,2","medicine_Data":[
      {
         "id":"1"
         "medname":"crosin","desc":"fever tab"
      },{
         "id":"2"
         "medname":"etzaa","desc":"shampoo"
      }]
  },{
  "id":"2","name":"abc","age":"20","sex":"F","medicine_id":"3","medicine_Data":[{
         "id":"3"
         "medname":"zaanta","desc":"pain killer"
      }]
  }]

我使用的查询是

SELECT json_object(
  'id',b.id,'name',b.name,'age',b.age,'sex',b.sex,'medicine_id',b.medicine_id,'medicine_data',json_arrayagg(json_object(
    'id',pt.id,'medname',pt.medname,'desc',pt.desc,))
  )
FROM patient b LEFT JOIN medication_master pt
ON b.medicine_id = pt.id
where b.id=1
GROUP BY b.id;

提前致谢