如何解决按字典python的值对列表进行排序
我需要一些帮助,如何使用算法选择排序根据字典的值对列表进行排序。我写了一些代码,但我不知道如何继续,代码工作。
months = {"January": 1,"February": 2,"march": 3,"April": 4,"May": 5,"June": 6,"July": 7,"August": 8,"September": 9,"October": 10,"November": 11,"December": 12}
L = ["march","January","December"]
例如按字典的值对列表进行排序
def month(L):
for i in months:
minpos = i
for j in range (months[i],len(L)):
if months[L[j]] > months[minpos]:
months[minpos] = months[L[j]]
L[j],L[minpos] = L[minpos],L[i]
return L
解决方法
您的代码:
months = {"January": 1,"February": 2,"March": 3,"April": 4,"May": 5,"June": 6,"July": 7,"August": 8,"September": 9,"October": 10,"November": 11,"December": 12}
L = ["March","January","December"]
将L中的月份名称(str)转换为对应的数字,然后进行排序。
num_L = sorted( [months[month] for month in L] )
将排序后的数字转换为相应的月份名称。
res = [k for number in num_L for k,v in months.items() if number == v]
在匹配月份名称之前,您可能需要一些类似 uppercase() 或 lower() 的字符串操作。
,新答案
- 创建具有
selection_sort
方法的类get_sorted()
,该方法将使用选择排序根据字典值对列表进行排序。 - 这里我们比较两个值,如果第一个值大于第二个,则交换两个值。重复此步骤,直到对整个列表进行排序。
class selection_sort:
"""Sort the list based on dictionary value using selection sort."""
def __init__(self,L):
self.months = {"January": 1,"December": 12}
self.L = L
def get_sorted(self):
""" sorting list."""
month_num = [self.months[i] for i in self.L]
flag = True # set Flag is True to enter the loop.
while flag:
flag = False # set Flag to False for no swaping done
for i in range(len(month_num)-1):
if month_num[i] > month_num[i+1]:
flag = True # set Flag to False if no swaping is done
# swap
month_num[i],month_num[i+1] = month_num[i+1],month_num[i]
L = [k for k,v in self.months.items() if v in month_num]
print(L)
return L
测试用例
-
您编写的测试是将
L
与Expected
进行比较。它应该将actual
与expected
进行比较。self.assertEqual(L,expected)
-
另外,expected =
["March","May","December","October","September"]
是不正确的。应该是["March","September","December"]
import unittest
from selectionSort import selection_sort
# @unittest.skip("")
class TestInPlace(unittest.TestCase):
def test_1(self):
L = ["December","March","May"]
obj = selection_sort(L)
actual = obj.get_sorted()
expected = ["March","December"]
self.assertEqual(actual,expected)
旧答案
试试这个,
#creating list L1
L1 = [months[L[i]] for i in range(len(L))]
print(L1)
#sorting list using algorithm selection sort
for i in range(1,len(L1)):
j = 0
if L1[j] > L1[i] :
L1[j],L1[i] = L1[i],L1[j]
print(L1)
#Replacing values with key
sorted_list = [ k for k,v in months.items() for i in L1 if i == v]
print(sorted_list)
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