如何解决如何生成一个文件,我们可以在其中获取维恩图中每个组合中表达的常见基因列表
我生成了一个维恩图,我可以使用 venn() 生成对交叉数据的访问,如下所示:
num Novembre Decembre Janvier Fevrier
0000 0 0 0 0 0
0001 21 0 0 0 1
0010 60 0 0 1 0
0011 9 0 0 1 1
0100 434 0 1 0 0
0101 0 0 1 0 1
0110 0 0 1 1 0
0111 0 0 1 1 1
1000 62 1 0 0 0
1001 7 1 0 0 1
1010 9 1 0 1 0
1011 20 1 0 1 1
1100 0 1 1 0 0
1101 0 1 1 0 1
1110 0 1 1 1 0
1111 0 1 1 1 1
attr(,"intersections")
attr(,"intersections")$`Janvier:Fevrier`
[1] "Qrob_P0051380.2" "Qrob_P0057520.2" "Qrob_P0111560.2" "Qrob_P0155280.2" "Qrob_P0196590.2" "Qrob_P0344390.2" "Qrob_P0425470.2" "Qrob_P0474120.2" "Qrob_P0730350.2"
attr(,"intersections")$`Novembre:Fevrier`
[1] "Qrob_P0104640.2" "Qrob_P0223890.2" "Qrob_P0286790.2" "Qrob_P0291840.2" "Qrob_P0418650.2" "Qrob_P0556330.2" "Qrob_P0765470.2"
attr(,"intersections")$`Novembre:Janvier`
[1] "Qrob_P0051350.2" "Qrob_P0051360.2" "Qrob_P0051620.2" "Qrob_P0051730.2" "Qrob_P0103750.2" "Qrob_P0297970.2" "Qrob_P0405980.2" "Qrob_P0472310.2" "Qrob_P0478790.2"
attr(,"intersections")$`Novembre:Janvier:Fevrier`
[1] "Qrob_P0051640.2" "Qrob_P0115060.2" "Qrob_P0122530.2" "Qrob_P0131080.2" "Qrob_P0155990.2" "Qrob_P0157520.2" "Qrob_P0181110.2" "Qrob_P0190180.2" "Qrob_P0190210.2" "Qrob_P0196560.2" "Qrob_P0232110.2" "Qrob_P0302630.2"
[13] "Qrob_P0388940.2" "Qrob_P0488960.2" "Qrob_P0503590.2" "Qrob_P0503600.2" "Qrob_P0556320.2" "Qrob_P0582310.2" "Qrob_P0740100.2" "Qrob_P0768850.2"
attr(,"intersections")$Fevrier
[1] "Qrob_P0052760.2" "Qrob_P0067620.2" "Qrob_P0070060.2" "Qrob_P0135090.2" "Qrob_P0155980.2" "Qrob_P0173120.2" "Qrob_P0196570.2" "Qrob_P0242780.2" "Qrob_P0263100.2" "Qrob_P0310350.2" "Qrob_P0361200.2" "Qrob_P0370740.2"
[13] "Qrob_P0454040.2" "Qrob_P0454080.2" "Qrob_P0492330.2" "Qrob_P0533420.2" "Qrob_P0551020.2" "Qrob_P0566900.2" "Qrob_P0571060.2" "Qrob_P0642020.2" "Qrob_P0669830.2"
........
我想为每个交叉点获取一个文件,该文件为我提供该交叉点的基因及其关联线,有没有一种有效的方法可以做到这一点?一个函数,一个脚本? 我尝试了一些方法,但它真的很慢而且效率不高,我有很多这种类型的数据要检索,我想优化一下。
我可以对两个表使用 compare() 但我不必比较 3 或 4 个表...
感谢您的帮助,并提前为您解答,
祝你有美好的一天,
阿卡
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