regex匹配字符串中所有* texttexttext

如何解决regex匹配字符串中所有* texttexttext

| 我需要一个正则表达式，它将匹配以*开头的所有字符串，直到遇到< 因此在此文本块中：

bob went to the *store and he bought a toy and <then he went outside *and went to his car for <a ride.

它会匹配

bob went to the *store and he bought a toy and

和

and went to his car for

如果没有\“ <\”，它将匹配所有行，直到行尾     

解决方法

        尝试这个：

<pre>
<?
$s = \'bob went to the *store and he bought a toy and <then he went outside *and went to his car for <a ride.\';

preg_match_all(\"/\\*([^<]+)/\",$s,$matched); 
print_r($matched);
?>

输出：

Array
(
    [0] => Array
        (
            [0] => *store and he bought a toy and 
            [1] => *and went to his car for 
        )

    [1] => Array
        (
            [0] => store and he bought a toy and 
            [1] => and went to his car for 
        )

)

    ,        应该是这样的： 使用PHP：

preg_match_all(\"#\\*(.+?)<#\",$stringWithText,$matches,PREG_SET_ORDER);
$mCount = count($matches);

foreach ($matches as $match)
    echo \"Matched: \" . $match[1] . \"<br/>\";

如果要跳过结尾\“ <\”，则将表达式更改为

#\\*(.+?)<?#

，并且如果要允许更改行，请使用以下标志：

preg_match_all(\"#\\*(.+?)<#si\",PREG_SET_ORDER);

注意表达式后面的si标志 希望能帮助到你     ,        试试

\\*(.+?)<

您可以使用此工具尝试使用正则表达式：http://gskinner.com/RegExr/ 编辑 要与字符串的最后一个“ 9” OR匹配，请使用：

\\*(.+?)[<|$.*]

    ,        我会用这样的东西

(?<=\\*).*?(?=<|$)

在Regexr上查看

(?<=\\*)

是后面的字符，它不匹配任何字符，但可以确保前面的字符是

*

.*?

匹配所有非贪婪的事物

(?=<|$)

是向前看的字符，它不匹配任何字符，但可以确保后面的字符是

<

或

$

（行尾）==>使用m（多行）修饰符，否则

$

仅匹配字符串，而不是行尾。