如何解决jQuery获取IP地址
| 古老的问题。需要找到解决方案。 这个: $ .getJSON(\“ http://jsonip.appspot.com?callback =?\”,函数(数据){ip = data.ip}); 似乎不再起作用:App Engine Error
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我发现了这个http://checkip.dyndns.org/
我使用加载(数据类型设置为jsonp)来尝试获取html,但我认为我做的不正确,或者无法完成。
有什么帮助吗?
谢谢堆栈;-)
解决方法
只需使用以下代码创建一个php文件:
回声\'[{\“ ip \”:\“ $ _ SERVER [\'REMOTE_ADDR \'] \”}] \';
然后使用JSON ping通
,
<!-- Require jQuery / Anyversion --><script type=\"text/javascript\" language=\"Javascript\" src=\"http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js\"></script>
<!-- Require EasyJQuery After JQuery --><script type=\"text/javascript\" language=\"Javascript\" src=\"http://api.easyjquery.com/easyjquery.js\"></script>
<script type=\"text/javascript\" language=\"Javascript\">
// 1. Your Data Here
function my_callback(json) {
alert(\"IP :\" + json.IP + \" \\nCountry: \" + json.Country);
}
function my_callback2(json) {
// more information at http://api.easyjquery.com/test/demo-ip.php
alert(\"IP :\" + json.IP + \" \\nCountry: \" + json.Country + \" City: \" + json.CityName + \" RegionName: \" + json.RegionName);
}
// 2. Setup Callback Function
// EasyjQuery_Get_IP(\"my_callback\"); // fastest version
EasyjQuery_Get_IP(\"my_callback2\",\"full\"); // full version
</script>
[IP] => 93.154.204.205
[ContinentCode] => NA
[ContinentName] => North America
[CountryCode2] => US
[CountryCode3] => USA
[COUNTRY] => US
[CountryName] => United States
[RegionName] => California
[CityName] => Garden Grove
[CityLatitude] => 33.7831
[CityLongitude] => -118.0271
[CountryLatitude] => 38
[CountryLongitude] => -98
[LocalTimeZone] => America/Los_Angeles
[REMOTE_ADDR] => 77.93.210.64
[HTTP_X_FORWARDED_FOR] =>
[CallingCode] => 1
[Population] => 307,212,123 (3)
[AreaSqKm] => 9,826,675 (4)
[GDP_USD] => 14.26 Trillion (1)
[Capital] => Washington,D.C.
[Electrical] => 120 V,60 Hz Type A Type B
[Languages] => English 82.1%,Spanish 10.7%,other Indo-European 3.8%,Asian and Pacific island 2.7%,other 0.7% (2000 census)
[Currency] => US Dollar (USD)
[Flag] => http://api.easyjquery.com/proips/flags/US.jpg
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