获取每个日期的总和

如何解决获取每个日期的总和

| 我正在用C＃编写一个程序，该程序可以读写sqlite（System.Data.sqlite）我有一张看起来像这样的桌子

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
1        1      10      1      2011-06-01 10:20:30.333
1        2      20      3      2011-06-01 10:20:30.444
2        1      100     11     2011-06-01 10:20:30.333
2        2      22      32     2011-06-01 10:20:30.444
1        1      20      2      2011-06-01 10:30:30.333
1        2      30      4      2011-06-01 10:30:30.444
2        1      22      22     2011-06-01 10:30:30.333
2        2      33      44     2011-06-01 10:30:30.444
1        1      10      1      2011-06-02 10:20:30.333
1        2      20      3      2011-06-02 10:20:30.444
2        1      11      11     2011-06-02 10:20:30.333
2        2      22      32     2011-06-02 10:20:30.444
1        1      20      2      2011-06-02 10:30:30.333
1        2      30      4      2011-06-02 10:30:30.444
2        1      22      22     2011-06-02 10:30:30.333
2        2      33      44     2011-06-02 10:30:30.444

我需要为每个用户从中获得三件事。 1）值1和2的每个产品在一天中的最后输入项总计，因此其一两个值即所有产品的总和。即，对于2011年1月1日的用户1，它将是Value1 = 50和Value2 = 6。我目前使用：

SELECT * FROM TickData AS a,;
(SELECT USERID,DATE(TIME) AS JUSTDATE,MAX(TIME) AS MTIME;
FROM TickData;
GROUP BY 1,2;
) AS b;
WHERE a.USERID = b.USERID;
AND a.TIME = b.MTIME;
AND STrftIME(\'%Y-%m\',a.TIME) = STrftIME(\'%Y-%m\',\'Now\');
AND a.USERID = 1;

这将返回：

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
1        1      20      2      2011-06-01 10:30:30.333
1        2      30      4      2011-06-01 10:30:30.444

对于2011-06-01。然后我遍历数据并在日期相同时添加值。给我Value1 = 50和Value2 = 6。 2）所有产品的“ Value1”每天最高条目合计。即，对于2011年2月1日的用户2，它将为Value1 = 133。

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
2        1      100     11     2011-06-01 10:20:30.333
2        2      33      44     2011-06-01 10:30:30.444

3）所有产品的“ Value1”每天最低条目合计。即，对于2011年6月1日的用户2，它将为Value1 = 44。

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
2        2      22      32     2011-06-01 10:20:30.444
2        1      22      22     2011-06-01 10:30:30.333

我还没有2或3的运气。有人有任何建议吗

解决方法

好的，周末我要锻炼自己 1）

SELECT sum(value1),sum(value2) FROM TickData AS a,(SELECT USERID,PRODID,DATE(TIME) AS JUSTDATE,MAX(TIME) AS MTIME
FROM TickData
GROUP BY 1,2,3
) AS b
WHERE a.USERID = b.USERID
AND a.TIME = b.MTIME
AND STRFTIME(\'%Y-%m\',a.TIME) = STRFTIME(\'%Y-%m\',\'NOW\')
AND a.USERID = 1
GROUP BY JUSTDATE

2）

SELECT sum(Mval) FROM TickData AS a,ID,MAX(value1) AS Mval
FROM TickData
GROUP BY 1,3
) AS b
WHERE a.USERID = b.USERID
AND a.ID = b.ID
AND STRFTIME(\'%Y-%m\',\'NOW\')
AND a.USERID = 2
GROUP BY JUSTDATE

3）

SELECT sum(Mval) FROM TickData AS a,MIN(value1) AS Mval
FROM TickData
GROUP BY 1,\'NOW\')
AND a.USERID = 2
GROUP BY JUSTDATE

编辑： 2和3可以通过一个查询完成：

SELECT sum(Mval),sum(Mval2) FROM TickData AS a,MAX(PL) AS Mval,MIN(PL) AS Mval2
FROM TickData
GROUP BY 1,\'NOW\')
AND a.USERID = 2
GROUP BY JUSTDATE