如何解决“抛出异常：写访问冲突”

如何解决如何解决“抛出异常：写访问冲突”

我正在编写一个简单的程序，该程序将创建一个链表，然后将输入作为每个学生的姓名和 GPA。

#pragma warning(disable:4996)
#include<stdio.h>
#include<stdlib.h>
#include<iostream>
#include<string>
using namespace std;

struct studentList {
    struct student* student;
    struct studentList* next;
}*list = NULL;

struct student {
    char* name;
    double gpa;
};

int main() {
    studentList* headPointer = NULL;            //create a head pointer to the list
    studentList* tailPointer = NULL;            //create a tail pointer to the list
    studentList* displayPointer = NULL;
    studentList* stuListPtr = NULL;
    student* stuPtr = NULL;
    char choice;
    double gpa;
    char* tempName = NULL;
    int count = 0;
while (1) {
    cout << "1. Add student record\n";
    cout << "2. display student records\n";
    cout << "3. Count number of records\n";
    cout << "4. Exit\n";
    cin >> choice;
    switch (choice) {
    case '1':
        count++;
        stuListPtr = (studentList*)( malloc(count * sizeof(studentList)));
        stuPtr = (student*)(malloc(count * sizeof(student)));
        cout << "What is the name of the student?\n";
        cin >> tempName;
        stuListPtr->student->name = tempName;
        cout << "What is his/her GPA?\n";
        cin >> stuListPtr->student->gpa;
        if (headPointer == NULL) {
            headPointer = stuListPtr;
            tailPointer = stuListPtr;
        }
        else if (headPointer != NULL) {
            tailPointer->next = stuListPtr;//memory of the SL type
        }
        stuListPtr->next;
        break;

当我输入'1'作为选择case 1的选项后，程序要求我输入名字，输入名字后，程序自动结束。我试图在名称为 tempName 的行上放置一个断点，弹出错误“抛出异常：写访问冲突”。任何人都可以帮我解决这个问题吗？

附言 stuListPtr->student->name = tempName; 下的绿色下划线表示“取消引用 NULL 指针 'stuListPtr'”

解决方法

欢迎来到 SO，你分配了你的指针，但你没有初始化它。由于这个原因，这条线失败了：

stuListPtr->student->name = tempName;

因为 stuListPtr 指向一个已分配但没有数据的地方。