org.springframework.ws.soap.client.SoapFaultClientException 使用 Spring WS WebServiceTemplate 时

如何解决org.springframework.ws.soap.client.SoapFaultClientException 使用 Spring WS WebServiceTemplate 时

面临以下问题：我有一个 wsdl 文件，用于通过 SOAP 传达我的服务和 CRM。请求的正文是通过从 wsdl 配置 java 文件来填充的。但是头必须手动写入。我正在使用以下技术发送我的请求：

 final Map<String,String> gateValues = new HashMap<>();
    final String username = Objects.requireNonNull(config).getSoapconf().getUsername();
    final String password = Objects.requireNonNull(config).getSoapconf().getpassword();
    final String webServices = Objects.requireNonNull(config).getSoapconf().getSessionType();
    gateValues.put("Usernametoken",username);
    gateValues.put("PasswordText",password);
    gateValues.put("SessionType",webServices);
    GetInput rq = new Getinput();
    rq.setMyParam(param);
    log.info("Requesting {}",param);
    try {
        Getoutput client = (Getoutput) getwebservicetemplate().marshalSendAndReceive(rq,(message) -> {
            if (message instanceof saajSoapMessage) {
                saajSoapMessage saajSoapMessage = (saajSoapMessage) message;
                SOAPMessage soapMessage = saajSoapMessage.getsaajMessage();
                SOAPPart soapPart = soapMessage.getSOAPPart();

                try {
                    SOAPEnvelope soapEnvelope = soapPart.getEnvelope();
                    SOAPHeader soapHeader = soapEnvelope.getHeader();

                    gateValues.forEach((key,value) -> {
                        try {
                            Name headerElementName = soapEnvelope.createName(
                                    key,PREFIX,NAMESPACE
                            );
                            System.out.println(headerElementName.getLocalName() + "\n" + headerElementName.getQualifiedname());
                            SOAPHeaderElement soapHeaderElement = soapHeader.addHeaderElement(headerElementName);
                            soapHeaderElement.setTextContent(value);
                        } catch (SOAPException e) {
                            // error handling
                        }
                    });

                    soapMessage.saveChanges();
                    soapMessage.writeto(System.out);
                    System.out.println(soapEnvelope.getHeader());
                } catch (SOAPException e) {
                    System.out.println();
                }
            }
        });
        return client;
    } catch (Exception e) {
        ExceptionUtils.getStackTrace(e);
    }

已经添加了最后一个捕获以查找错误。从 webservicetemplate 类的 doSendAndReceive 方法中删除错误 org.springframework.ws.soap.client.soapFaultClientException。

  <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
        <SOAP-ENV:Header>
            <PasswordText xmlns="http://***.com/services">myPass</PasswordText>
            <SessionType xmlns="http://****.com/services">mySessionType</SessionType>
            <Usernametoken xmlns="http://***.com/services">myUsName</Usernametoken>
        </SOAP-ENV:Header>
        <SOAP-ENV:Body><ns2:Get_Input xmlns:ns2="http://***.com/UI" xmlns:ns3="http://***.com/xml/%20External">
            <ns2:param>238068014416</ns2:param>
        </ns2:Get_Input>
        </SOAP-ENV:Body>
        </SOAP-ENV:Envelope>

缺少什么？为什么 SOAPUI - 它是有效的。客户端请求是按照来自 Add SoapHeader to org.springframework.ws.WebServiceMessage

的最后一个回答的示例进行的