查找是否存在不符合指定条件的子数组

如何解决查找是否存在不符合指定条件的子数组

我有一个名为 orgnisation 的数组。该数组包含组织中的单位。每个单元都是一个具有数组 staff 的对象。一些员工拥有 A 类驾驶执照 (driversLicenseA)。

checkDriversLicense 函数必须经过组织，查看每个单元是否至少有一个人持有驾照。全组织有单位无驾驶证人员的，必须退回。

organisation: [
  {
    id: 1,title: 'Sub Org 1',staff: [
      {
        id: 11,name: 'John',driversLicenseA: false,},{
        id: 12,name: 'Mike',driversLicenseA: true,{
        id: 13,name: 'Daniel',}
    ]
  },{
    id: 2,title: 'Sub Org 2',staff: [
      {
        id: 21,name: 'Gustav',{
        id: 22,name: 'Sandra',{
        id: 23,name: 'Nikita',{
    id: 3,title: 'Sub Org 3',staff: [
      {
        id: 31,name: 'Carla',{
        id: 32,name: 'Augustin',{
        id: 33,name: 'Martin',]

public checkDriversLicense(organisation: any[]) {
  let driversLicenseA =  organisation.find((element) => element.staff != null && element.staff?.length != 0 && element.staff?.some((item) => item.driversLicenseA == true));     
  return driversLicenseA ;

}

但是这个代码会检查所有单位，如果全机构有一个人有驾照，则返回true（如果有其他单位没有人员持有驾照，则不返回false）。 如何修改以返回正确的结果？

我希望退回 fasle，因为 Sub Org 2 和 Sub Org 3 没有拥有驾照的员工。

解决方法

您可以使用 Array#every 查询 organisation abd 并使用 Array#some 查询每个 staff。

const
    organisation = [{ id: 1,title: 'Sub Org 1',staff: [{ id: 11,name: 'John',driversLicenseA: false },{ id: 12,name: 'Mike',driversLicenseA: true },{ id: 13,name: 'Daniel',driversLicenseA: false }] },{ id: 2,title: 'Sub Org 2',staff: [{ id: 21,name: 'Gustav',{ id: 22,name: 'Sandra',{ id: 23,name: 'Nikita',{ id: 3,title: 'Sub Org 3',units: [{ id: 31,name: 'Carla',{ id: 32,name: 'Augustin',{ id: 33,name: 'Martin',driversLicenseA: false }] }],eachOrganisationHasLicenceA = organisation.every(({ staff }) =>
        staff.some(({ driversLicenseA }) => driversLicenseA)
    );

console.log(eachOrganisationHasLicenceA);

,

虽然不是最紧凑的代码，但我认为这很容易理解

public checkDriversLicence(organisation: any[]) {
  for (let unit of organisation) {
    // each unit should have at least 1 driver's licence
    if (unit.staff.filter(e => e.driversLicenceA).length === 0) {
      // this unit does not have anyone with a driver's licence
      return false;
    }
  }
  // if we reach this point,each unit has at least one staff member with a driver's licence
  return true;
}

,

这里有一些应该有帮助的东西。

let organization = [
      {
        id: 1,staff: [
          {
            id: 11,driversLicenseA: true,},{
            id: 12,{
            id: 13,}
        ]
      },{
        id: 2,driversLicenseA: false,{
        id: 3,staff: [
          {
            id: 21,{
            id: 22,{
            id: 23,{
        id: 4,staff : [
          {
            id: 31,{
            id: 32,{
            id: 33,];

 // lets loop over the collection and try to acces the staff property!

organization.forEach(( or ) => { 
  drivers = or.staff; // these are our staff.

  // lets loop over the staffs and see if atleast one does not meet the criteria.
  // reduce function will allow us to iterate all the values and return a single value at the end.
  // we simply compare the value from each iteration to the previous value.
  // ie check if the current value is equal to the previous iteration value and return it.
  // The value returned at each iteration is used for next one and so on.
  // The code below assumes if any value at any iteration is false all values will be false.
  // at the end only values with true wil be the one that match our requirements.

  // check object 1 and 2
  let valid = drivers.reduce( ( accumulator,currentValue) => {
    return currentValue.driversLicenseA == accumulator;
  } );
    
  // lastly check if the value returned is as per our ask and print.    
  if(valid){
    console.log("Not applicable to Orgnization Id :" + or.id );
  }else{
   console.log("applicable to Organization Id :" +  or.id );
  }
        

});