如何解决使用 reduce() 和 Typescript 解析嵌套对象
我实际上是在尝试将一些 Javascript 代码转换为 Typescript,但是我在以下功能方面遇到了问题。它的目的是解析一些内容(从 JSON.parse() 构建的嵌套对象),当被调用时,例如:t('common.error')
。
const i18nContent = {
common: {
error: {
missing_translation: 'Missing translation',missing_posts: 'Some articles are not available in this language',},languages_available: 'This article is available in other languages'
}
const t = (key) => {
const kArray = key.split('.')
// Parsing possibly nested object
const keyvalue = kArray.reduce((o,k) => ((o && o[k] !== 'undefined') ? o[k] : undefined),i18nContent)
return keyvalue || key
}
我尝试了这种方法,它似乎有效,但对我来说似乎很丑……:/
type I18nContent = Record<string,unkNown> // Content value Could be a string,or a nested object
type I18n = Record<string,I18nContent> // API always returns an object with namespace as key,and object (possibly nested) as value
const i18nContent: I18n = {
common: {
error: {
missing_translation: 'Missing translation',missing_posts: 'Some articles are not available in this language'
},languages_available: 'This article is available in other languages'
}
}
const t = (key: string): string => {
const kArray = key.split('.')
const keyvalue = kArray.reduce((o: unkNown,k: string) => {
if (o && typeof o === 'object' && Object.keys(o).length && o[k as keyof typeof o] !== 'undefined') {
return o[k as keyof typeof o]
} else {
return undefined
}
},i18nContent)
return typeof keyvalue === 'string' ? keyvalue : key
}
我对 Typescript 还很陌生,所以我很乐意得到一些反馈,或许还有关于这个 refacto 的建议?
提前谢谢!
解决方法
因为 reduce
函数返回类型作为初始值的类型,所以我在您的代码中稍作更改以支持 i18n 嵌套多级对象。
interface ITranslationContent {
[key: string]: string | ITranslationContent;
}
const i18nContent: ITranslationContent = {
common: {
error: {
missing_translation: 'Missing translation',missing_posts: 'Some articles are not available in this language',http_code: {
unauthorized: '401'
}
},languages_available: 'This article is available in other languages'
}
}
const t = (key: string): string | ITranslationContent => {
const kArray = key.split('.')
let res: string | ITranslationContent = i18nContent;
kArray.forEach((k: string) => {
res = typeof res === 'string' ? res : res[k];
})
return res || key;
}
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。