如何解决feof 导致分段错误核心转储错误?
我正在尝试创建一个从文件中获取动态分配的字符串的函数,忽略前导空格并继续直到它再次到达空格,但我一直收到“分段错误(核心转储)”错误。我尝试使用 valgrind 来查找原因,它说明了 feof
Invalid read of size 4
==1155740== at 0x48EDE24: feof (feof.c:35)
==1155740== by 0x1095E7: my_string_extraction (my_string.c:73)
==1155740== by 0x109285: main (main.c:10)
==1155740== Address 0x0 is not stack'd,malloc'd or (recently) free'd
但是,当我将其复制到 Visual Studio 时,它可以正常工作
Status my_string_extraction(MY_STRING hMy_string,FILE* fp)
{
char currCh;
int i = 0;
int x = 0;
int wordStart = 0;
struct My_string* temp = hMy_string;
char* tempData;
while (!feof(fp))
{
currCh = fgetc(fp);
if ((currCh == ' ' || currCh == '\n' || currCh == '\t' || feof(fp)) && wordStart != 0)
{
temp->data[i] = '\0';
temp->size = i - 1;
fseek(fp,-1,SEEK_CUR);
return SUCCESS;
} else if (currCh == ' ' || currCh == '\n' || currCh == '\t') {
} else {
if ((i+1) >= temp->cap)
{
tempData = (char*) malloc(sizeof(char) * temp->cap * 2);
for(x = 0; x < temp->size; x++)
{
tempData[x] = temp->data[x];
}
free(temp->data);
temp->data = tempData;
temp->cap = temp->cap * 2;
}
wordStart = 1;
temp->data[i] = currCh;
i++;
temp->size = i;
}
}
temp->data[i + 1] = '\0';
return FAILURE;
}
主要
#include <stdio.h>
#include <stdlib.h>
#include "my_string.h"
int main(int argc,char* argv[])
{
MY_STRING hMy_string = NULL;
FILE* fp;
hMy_string = my_string_init_default();
fp = fopen("Spring2019/COMP1020/HANGMAN/simple.txt","r");
my_string_extraction(hMy_string,fp);
my_string_destroy(&hMy_string);
//fclose(fp);
return 0;
}
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