cout 语句中 C++ 中的 Pre 和 Post 增量

如何解决cout 语句中 C++ 中的 Pre 和 Post 增量

#include<iostream>
using namespace std;
int main(){
    int t;
    t=1;
    cout<<"--1--"<<"\n";
    cout<<++t + ++t<<"\n";
    t=1;
    cout<<++t <<"\t"<< ++t<<"\n";
    t=1;
    cout<<"--2--"<<"\n";
    cout<<++t + t++<<"\n";
    t=1;
    cout<<++t <<"\t"<< t++<<"\n";
    t = 1;
    cout<<"--3--"<<"\n";
    cout<<++t + t++ + ++t<<"\n";
    t = 1;
    cout<<++t <<"\t"<< t++ <<"\t"<< ++t<<"\n";
    t = 1;
    cout<<"--4--"<<"\n";
    cout<<++t + t++ + t++<<"\n";
    t = 1;
    cout<<++t <<"\t"<< t++ <<"\t"<< t++<<"\n";
    t = 1;
    cout<<"--5--"<<"\n";
    cout<<t++ + t++ + t++<<"\n";
    t = 1;
    cout<<t++ <<"\t"<< t++ <<"\t"<< t++<<"\n";
    t = 1;
    cout<<"--6--"<<"\n";
    cout<<t++ + t++ + ++t<<"\n";
    t = 1;
    cout<<t++ <<"\t"<< t++ <<"\t"<< ++t<<"\n";
    t = 1;
    cout<<"--7--"<<"\n";
    cout<<++t + ++t + t++<<"\n";
    t = 1;
    cout<<++t <<"\t"<< ++t <<"\t"<< t++<<"\n";
    t = 1;
    cout<<"--8--"<<"\n";
    cout<<++t + t++ + ++t + ++t<<"\n";
    t = 1;
    cout<<++t <<"\t"<< t++ <<"\t"<< ++t <<"\t"<< ++t<<"\n";
    t=1;
    cout<<"--9--"<<"\n";
    cout<<++t + t++ + ++t + t++<<"\n";
    t=1;
    cout<<++t <<"\t"<< t++ <<"\t"<< ++t <<"\t"<< t++<<"\n";
}

在这里，我试图弄清楚结果如何。

--1--
6
3       3
--2--
5
3       1
--3--
9
4       2       4
--4--
8
4       2       1
--5--
6
3       2       1
--6--
7
3       2       4
--7--
9
4       4       1
--8--
14
5       3       5       5
--9--
13
5       3       5       1