如何使用标准构建器为内部连接编写子查询并读取多选中的计数

如何解决如何使用标准构建器为内部连接编写子查询并读取多选中的计数

下面是相应的 MysqL 查询及其工作查询：

  select tab4.id,tab4.name,tab7.city,tab7.state,tab7.phone,tab5.status_priority,tab5.model,tab5.code,tab5.number,tab5.ds_formatted_timestamp
  group_concat( distinct tab6.position),coalesce(b.counts,0) as count
  from table1 tab1
  inner join table2 tab2 on tab1.organization_id=tab2.organization_id
  inner join table3 tab3 on tab2.organization_id=tab3.organization_id
  inner join table4 tab4 on tab3.site_id=tab4.site_id
  inner join table5 tab5 on tab4.site_id=tab5.site_id
  inner  join(select count(component_name) as counts,device_id from table6 group by device_id) b on ?
   b.device_id =tab5.device_id
  left outer join table6 tab6 on tab5.id=tab6.id
  left outer join table7 tab7 on tab4.address_id=tab7.address_id
  where tab1.user_id='test@gmail.com'
  group by tab5.id
   order by tab5.status_priority desc;

Criteriabuilder 下面是工作代码

 Root<table1> user = criteriaQuery.from(table1.class);`
 Join<Object,Object> user2 = user.join("table2",JoinType.INNER);
 Join<Object,Object> user3 = user2.join("table3",Object> user4 = user3.join("table4",Object> user5 = user4.join("table5",Object> user6 = user5.join("table6",JoinType.LEFT);
 Join<Object,Object> user7 = user5.join("table7",JoinType.LEFT);

我添加了以下几行，它可以工作，但不知道如何使用标准构建器编写

 coalesce(b.counts,0) as count `
 join(select count(component_name) as counts,device_id from table6 group by device_id) b on b.device_id  =tab5.device_id

如何使用标准构建器 (JPQL) 为此编写子查询？