如何解决将排序序号显示为列表中的计数
system info com1 command set
system info com2 command set
system command set1 information description test
system command 21-22 information description pass
system command T1-T2-T3 information description file
system command commonset information description info
和下面的命令
awk '/system command/&&/information description/ { gsub("\"","") ; print ++ OFS") Command = " $3}' inputfile.txt
给我以下输出
1) Command = set1
2) Command = 21-22
3) Command = T1-T2-T3
4) Command = commonset
有没有办法让我的命令列表计数不是简单的数字而是排序序数 并有这样的输出
1st) Command = set1
2nd) Command = 21-22
3rd) Command = T1-T2-T3
4th) Command = commonset
解决方法
没有内置函数来获取该序数。我们需要动手写下这段代码:
awk 'function ordinal(i,mod,str) {mod = i%10; str=i; if (i~/1[1-3]$/) str=str "th"; else if (mod==1) str=str "st"; else if (mod==2) str=str "nd"; else if (mod==3) str=str "rd"; else str=str "th"; return str;} /system command/&&/information description/ { gsub(/"/,"") ; print ordinal(++i) ") Command = " $3}' file
1st) Command = set1
2nd) Command = 21-22
3rd) Command = T1-T2-T3
4th) Command = commonset
扩展形式:
awk '
function ordinal(i,str) {
mod = i%10
str = i
if (i~/1[1-3]$/) # for numbers ending in 11,12,13
str = str "th"
else if (mod==1)
str = str "st"
else if (mod==2)
str = str "nd"
else if (mod==3)
str = str "rd"
else
str = str "th"
return str
}
/system command/&&/information description/ {
gsub(/"/,"")
print ordinal(++i) ") Command = " $3
}' file
实现上述功能的另一种方法是:
function ordinal(num,idx,sfxs) {
split("st nd rd th",sfxs," ")
idx = ( (num ~ /[123]$/) && (num !~ /1[123]$/) ? num % 10 : 4 )
return num sfxs[idx]
}
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