如何解决是否可以设置海龟相对于屏幕大小的位置
假设我的屏幕大小为 10,10
和 2,2 的 pos
如果屏幕大小更改为 5,5
pos 将是 1,1
或者有没有办法改变屏幕分辨率?
解决方法
turtle 会自动设置一个 ScrolledCanvas
,因此,调整窗口大小会尝试将事物保持在大致相同的位置,但存在限制。
您可以先将海龟放在成比例的位置,然后从该比例开始绘制。
只需将您的大小和移动视为窗口的分区。使用对角线作为主要维度,然后从那里开始。
这就是可缩放矢量图形的本质 -- https://en.wikipedia.org/wiki/Vector_graphics
#! /usr/bin/python3
from math import sqrt
from random import uniform
from turtle import Turtle,Screen
turtle,screen = Turtle(),Screen()
turtle.penup()
turtle.speed( 0 )
red,green,blue = 0.95,0.95,0.95
screen.bgcolor( red,blue )
##Width,Height = 300,300
Width,Height = 600,600
## Pythag. A squared +B squared = C squared
Diag = sqrt( (Width *Width) +(Height *Height) )
stepsize = Diag /100
screen.screensize( Width,Height ) ## canvas size to begin with
## window frame. by adding a few pixels,you avoid scrollbars
screen.setup( width = Width *1.03,height = Height *1.03 )
for i in range( 50 ): ## clouds
light = uniform( 0.8,1 )
turtle.pencolor( light,light,light )
turtle.pensize( stepsize *uniform( 0.5,5 ) )
turtle.setheading( uniform( 0.0,360 ) )
turtle.goto( Width *uniform( -0.5,0.5 ),Height *uniform( 0.0,0.5 ) )
turtle.pendown()
turtle.forward( stepsize *uniform( 0.1,1 ) )
turtle.penup()
red,blue = 0.0,0.25,0.5
for i in range( 25 ): ## scribble water
green += 0.01
blue += 0.02
water_level = Height *0.15 +(i *stepsize)
turtle.goto( -Width *0.55,-water_level )
turtle.pencolor( red,blue )
turtle.pensize( stepsize +i )
turtle.pendown()
turtle.goto( Width *0.55,-water_level )
turtle.penup()
red,0.95
turtle.goto( Width *0.25,Height *0.333 )
turtle.setheading( 45 )
turtle.pendown()
for i in range( 20 ): ## draw sun
red -= 0.0111
green -= 0.02
blue -= 0.0225
turtle.pencolor( red,blue )
turtle.pensize( stepsize *(30 -i) )
turtle.forward( stepsize /5 )
turtle.hideturtle()
screen.exitonclick()
## eof ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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