从 RSAUtils.encryptByPublicKey (Java) 到 openssl_public_encrypt (PHP)

如何解决从 RSAUtils.encryptByPublicKey (Java) 到 openssl_public_encrypt (PHP)

我正在尝试从 Java 代码中使用 openssl_public_encrypt 在 PHP 中进行转换，但无法在列表中管理以获取输出。

如果有人可以提供帮助，我们将不胜感激

MerchantPublicSecretKey = 'MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQDrXM8q2qrEuH+xFVcEpeiV4yX7r/5+SsjgLD/OF3VPYqKA07xOklLXhJqT8Shjtu/uye9BahqajqOiP9PjqAsN1amGodE1POhsAO537Av+pIh1sX1ULr+0fzxWzwphE3SX2dImTwWWxdZZB45P2GMtR1F+jA4E2Ud8oO1KIaX++QIDAQAB'

userInfoJson = {
         "payCardNo":"test1","payCardBank":"test2","payCardBranch":"test3"        
   } 

Java Code
sign = =Base64Utils.encode(RSAUtils.encryptByPublicKey(userInfoJson.getBytes("UTF-8"),MerchantPublicSecretKey));

解决方法

我设法解决了这个问题，如果对这里的人有帮助，那就是解决方案

$app_secret = 'MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQDrXM8q2qrEuH+xFVcEpeiV4yX7r/5+SsjgLD/OF3VPYqKA07xOklLXhJqT8Shjtu/uye9BahqajqOiP9PjqAsN1amGodE1POhsAO537Av+pIh1sX1ULr+0fzxWzwphE3SX2dImTwWWxdZZB45P2GMtR1F+jA4E2Ud8oO1KIaX++QIDAQAB';

$user_data= [
  "payCardNo" => "test1","payCardBank"  =>  "test2","payCardBranch"  =>  "test3"
];

function encryptData ($user_data){
    $user = json_encode($user_data,JSON_FORCE_OBJECT);
    $pub_key = chunk_split($app_secret,64,"\n");
    $pub_key = "-----BEGIN PUBLIC KEY-----\n" . $pub_key . "-----END PUBLIC KEY-----\n";
    $key = openssl_pkey_get_public($pub_key);

    $result  = '';
    for($i = 0; $i < strlen($user) / 117; $i++  ) {
        $data = substr($user,$i * 117,117);
        openssl_public_encrypt ($data,$encrypt,$key);
        $result .= $encrypt;
    }
    return base64_encode($result);
}

// usage
$encrypted_data = encryptData($user_data);