在生成的 PDF 中保留原始段落

如何解决在生成的 PDF 中保留原始段落

经过多次尝试,我无法从“SOME_PARAGRAPHS”路径生成尊重原始段落或加载文本的 pdf。

任何提示将不胜感激。

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:output method="xml" encoding="ISO-8859-1" doctype-public="-//big.faceless.org//report" />
    <xsl:template match="INFORMEMEDICO">
        <pdf>
            <head>
            </head>
            
            <body size="A4" header-height="15mm" footer-height="15mm">

                <br/>
                
                <!-- A (not show) -->
                <fo:block linefeed-treatment="preserve"><xsl:value-of select="SOME_PARAGRAPHS"/></fo:block>
            
                <br/>
            
                <!-- B (show but without respecting original paragraphs) -->
                <p><xsl:value-of select="SOME_PARAGRAPHS"/></p>                         
            
                <pbr/>          
            
            </body>
        </pdf>                          
    </xsl:template>
</xsl:stylesheet>

...具有:

<SOME_PARAGRAPHS>
                Candy cookie topping cotton candy icing pastry tart danish dessert. 

                Icing carrot cake gingerbread candy powder muffin soufflé fruitcake sweet roll.

                Wafer toffee topping jelly-o sesame snaps oat cake pie marzipan lemon drops.
</SOME_PARAGRAPHS>

这里没有“SOME_PARAGRAPHS”参与的简化版:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:output method="xml" encoding="ISO-8859-1"
        doctype-public="-//big.faceless.org//report" />
    <xsl:template match="INFORMEMEDICO">
        <pdf>
            <head>
            </head>
            
            <body size="A4" header-height="15mm" footer-height="15mm">

                <br/>
                
                <!-- (not show) -->
                <fo:block linefeed-treatment="preserve">
                    Candy cookie topping cotton candy icing pastry tart danish dessert. 

                    Icing carrot cake gingerbread candy powder muffin soufflé fruitcake sweet roll.

                    Wafer toffee topping jelly-o sesame snaps oat cake pie marzipan lemon drops.                
                </fo:block>
            
                <br/>
                        
                <pbr/>          
            
            </body>
        </pdf>                          
    </xsl:template>
</xsl:stylesheet>

解决方法

代替:

<xsl:value-of select="SOME_PARAGRAPHS"/>

您可能想要:

<xsl:apply-templates select="SOME_PARAGRAPHS"/>

然后你需要处理那些 SOME_PARAGRAPHS 之类的模板

  <xsl:template match="SOME_PARAGRAPHS">
    <fo:block linefeed-treatment="preserve">
      <xsl:apply-templates select="@*|node()"/>
    </fo:block>
  </xsl:template>

我建议从 xsl intro

开始

如果您熟悉 xsl,请执行 intro xsl-fo

,

我已经能够通过在Java后端分解段落来解决它:

StringTokenizer textoDictamenVidaLineas = new StringTokenizer(textoDictamenVida,"\n");
String linea;
while (textoDictamenVidaLineas.hasMoreTokens()) {
    linea = textoDictamenVidaLineas.nextToken();
    documentoXML.append("<SOME_PARAGRAPHS>" + linea + "</SOME_PARAGRAPHS>\n");
}

并在模板中使用它:

<xsl:for-each select="SOME_PARAGRAPHS">
    <p><xsl:value-of select="."/></p>
</xsl:for-each>

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