如何解决PHP jQuery Tabledit 选择选项
我正在尝试使用 jQuery tabledit
插件制作动态表。所以我有一张包含用户的表和一张包含用户类型(管理员、员工、客户)的表。这两个表之间的关系是通过 user_type_id
。我需要的是选择表 user_type
中的选项,因此当管理员想要编辑有关某些用户的信息时,他可以在选择中查看 user_type
表中的值,并且当他从中选择选项时选择,数据库中的数据将被更新。
这是两个表的关系 employess.PHP
<?PHP
$con = MysqLi_connect("localhost","root","","gym_project_db");
$query = "SELECT * FROM user WHERE user_type_id = 1";
$result = MysqLi_query($con,$query);
$query2 = "SELECT * FROM user_type";
$result2 = MysqLi_query($con,$query2);
?>
<!DOCTYPE html>
<html>
<head>
<title></title>
<link rel="stylesheet" type="text/css" href="css/main_page.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<script src="js/jquery.tabledit.js"></script>
<script src="js/jquery.multi-select.js"></script>
</head>
<body>
<div class="wrapper">
<div class="sidebar">
<h2>Gym management system</h2>
<ul>
<li><a href="#"><i class="fas fa-home"></i>Dashboard</a></li>
<li><a href="employess.PHP"><i class="fas fa-user"></i>Employees</a></li>
<li><a href="#"><i class="fas fa-address-card"></i>Clients</a></li>
<li><a href="#"><i class="fas fa-project-diagram"></i>Subscriptions</a></li>
<li><a href="#"><i class="fas fa-blog"></i>Branches</a></li>
<li><a href="#"><i class="fas fa-address-book"></i>Cards</a></li>
<li><a href="#"><i class="fas fa-address-book"></i>Profile</a></li>
<li><a href="#"><i class="fas fa-map-pin"></i>logout</a></li>
</ul>
</div>
<div class="main_content">
<div class="header">Welcome!! Have a nice day.</div>
<div class="info">
<div class="employess">
<table id="editable_table" class="table table-bordered table-striped">
<thead>
<tr>
<th>User_id</th>
<th>Username</th>
<th>Password</th>
<th>Name</th>
<th>Surname</th>
<th>EGN</th>
<th>Email</th>
<th>Phone</th>
<th>Address</th>
<th>User_type_id</th>
</tr>
</thead>
<tbody>
<?PHP while($row = MysqLi_fetch_array($result)){ ?>
<tr>
<td> <?= $row["user_id"] ?></td>
<td> <?= $row["username"] ?></td>
<td> <?= $row["password"] ?></td>
<td> <?= $row["name"] ?></td>
<td> <?= $row["surname"] ?></td>
<td> <?= $row["egn"] ?></td>
<td> <?= $row["email"] ?></td>
<td> <?= $row["phone"] ?></td>
<td> <?= $row["address"] ?></td>
<?PHP
$user_type_query = MysqLi_query($con,"SELECT user_type_id,user_type FROM user_type WHERE user_type_id = $row[9]");
$typerow = MysqLi_fetch_array($user_type_query);
?>
<td><?= $typerow[1]; ?></td>
</tr>
<?PHP }?>
</tbody>
</table>
</div>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$('#editable_table').tabledit({
url:'employee_action.PHP',columns:{
identifier:[0,"user_id"],editable:[[1,'username'],[2,'password'],[3,'name'],[4,'surname'],[5,'egn'],[6,'email'],[7,'phone'],[8,'address'],[9,'user_type_id']
]
},restoreButton:false,onSuccess:function(data,textStatus,jqXHR)
{
if(data.action == 'delete')
{
$('#'+data.id).remove();
}
}
});
});
</script>
employee_action.PHP
<?PHP
$connect = MysqLi_connect("localhost","gym_project_db");
$input = filter_input_array(INPUT_POST);
if($input["action"] === 'edit')
{
$query = "
UPDATE user
SET
username = '". $input["username"] ."',password = '". $input["password"] ."',name = '". $input["name"] ."',surname = '". $input["surname"] ."',egn = '". $input["egn"] ."',email = '". $input["email"] ."',phone = '". $input["phone"] ."',address = '". $input["address"] ."'
WHERE user_id = '".$input["user_id"]."'
";
MysqLi_query($connect,$query);
}
if($input["action"] === 'delete')
{
$query = "
DELETE FROM user
WHERE user_id = '".$input["user_id"]."'
";
MysqLi_query($connect,$query);
}
echo json_encode($input);
?>
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