C++ 中不允许使用限定名称，已在 C++ 17 中编译

如何解决C++ 中不允许使用限定名称，已在 C++ 17 中编译

我正在尝试关注 John Horton 在 Beginning C++ Game Programming 中的 Zombie Arena 项目。 但是，Pickup.h 给我带来了问题。

class Pickup
{
private:
    //Start value for health pickups
    const int HEALTH_START_VALUE = 50;
    const int AMMO_START_VALUE = 12;
    const int START_WAIT_TIME = 10;
    const int START_SECONDS_TO_LIVE = 5;

    // The sprite that represents this pickup
    Sprite m_Sprite;

    // The arena it exists in
    IntRect m_Arena;

    // How much is this pickup worth?
    int m_Value;

    // What type of pickup is this? 
    // 1 = health,2 = ammo
    int m_Type;

    // Handle spawning and disappearing
    bool m_Spawned;
    float m_SecondsSinceSpawn;
    float m_SecondsSinceDeSpawn;
    float m_SecondsToLive;
    float m_SecondsToWait;

    // Public prototypes go here
public:

    Pickup::Pickup(int type);

    // Prepare a new pickup
    void setArena(IntRect arena);

    void spawn();

    // Check the position of a pickup
    FloatRect getPosition();

    // Get the sprite for drawing
    Sprite getSprite();

    // Let the pickup update itself each frame
    void update(float elapsedTime);

    // Is this pickup currently spawned?
    bool isSpawned();

    // Get the goodness from the pickup
    int gotIt();

    // Upgrade the value of each pickup
    void upgrade();

};

当我尝试编译程序时，我从 Pickup::Pickup(int type) 的成员声明错误中得到一个非法限定名称。可能有什么问题？我试图调试这个没有成功。请帮忙。我已经在用 C++ 17 编译了。

解决方法

代替构造函数的这个声明

[hallo: {'name': 'Peter','lastname': 'Richard'}]

写

Pickup::Pickup(int type);

构造函数声明的限定名称不正确，但据我所知，某些编译器（如 MS VS）允许此类声明。

您可以在类定义之外的成员函数定义中使用成员函数的限定名称。