从 NamedTuple 类继承？

如何解决从 NamedTuple 类继承？

我最初的愿望是让一个类继承自 NamedTuple：首先以 NamedTuple 的方式启动它，然后执行一个没有参数的函数。为了示例起见，我们将 3D 向量和最终操作视为归一化。这是代码。

from collections import namedtuple
from math import sqrt

Vector1 = namedtuple("Vector1","x y z")
# a namedtuple class that represents 3D vectors

class Vector2:
    '''a class that represents 3D vectors'''
    def __init__(self,x,y,z):
        self.x = x
        self.y = y
        self.z = z

    def __str__(self):
        return f"{self.x:.2f} {self.y:.2f} {self.z:.2f}"


class Unit1(Vector1):
    '''a namedtuple class representing a 3D vector,that 
normalizes itself at construction'''
    def __init__(self,*args):
        super().__init__(*args)
        norm = sqrt(self.x**2 + self.y**2 + self.z**2)
        self.x /= norm
        self.y /= norm
        self.z /= norm


class Unit2(Vector2):
    '''a class representing a 3D vector,that normalizes itself 
at construction'''
    def __init__(self,*args):
        super().__init__(*args)
        norm = sqrt(self.x**2 + self.y**2 + self.z**2)
        self.x /= norm
        self.y /= norm
        self.z /= norm

c = Vector1(2,3,4)
print(c)

c = Vector2(2,4)
print(c)

c = Unit2(2,4)
print(c)

c = Unit1(2,4) # fails
print(c)

它返回：

Vector1(x=2,y=3,z=4)
2.00 3.00 4.00
0.37 0.56 0.74
Traceback (most recent call last):
  File "test.py",line 46,in <module>
    c = Unit1(2,4) # fails
  File "test.py",line 21,in __init__
    super().__init__(*args)
TypeError: object.__init__() takes exactly one argument (the instance to initialize)

令我困惑的是基类（Vector1 和 Vector2）如何接受相同的参数，而子类却有不同的行为（即 Unit2 按预期工作，但 {{1 }} 调用 Unit1 失败）。如何解释这一点，以及如何修复 super().__init__() 使其表现得像 Unit1 而不必重新定义笨拙的自制 Unit2？