如何解决PHP删除具有多个值的数组内的多个数组键
我发现我无法弄清楚所需的输出。
我有 JSON 原始数据包含这个：
Array
(
[data] => Array
(
[0] => Array
(
[title] => currency1
[tickers] => Array
(
[0] => USD
)
)
[1] => Array
(
[title] => currency2
[tickers] => Array
(
[0] => USD
[1] => EUR
)
)
[2] => Array
(
[title] => currency3
[tickers] => Array
(
[0] => USD
)
)
)
)
这是我试过的
$num =0;
foreach ($json_data as $key => $story){
$num++;
foreach($story as $subkey => $subvalue){
if(is_array($subvalue)){
$title = $story[$subkey]['title'];
$tickers = $story[$subkey]['tickers'][$num];
foreach($tickers as $key2 => $val2){
if($val2>=1){
unset($story);
}else{
//echo output
}
}
}
}
所需输出示例：
curreny1 Key is 0 and tickers is USD
curreny3 Key is 2 and tickers is USD
解决方法
您应该能够循环遍历源数据的 data 键，提取标题和代码并在代码为 1 时输出结果：
foreach ($json_data['data'] as $key => $story) {
$tickers = $story['tickers'];
if (count($tickers) != 1) continue;
$title = $story['title'];
echo "$title Key is $key and tickers is {$tickers[0]}\n";
}
输出（用于您的示例数据）：
currency1 Key is 0 and tickers is USD
currency3 Key is 2 and tickers is USD
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